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marta [7]
3 years ago
5

Which is most likely to help an introduced species become invasive?

Chemistry
1 answer:
7nadin3 [17]3 years ago
7 0
An introduced species could be invasive if it can outcompete native species for resources. Examples are light, nutrients, water, food etc.
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Give the name of one or more polysaccharides that matches each of the following descriptions:
adell [148]

Answer:

A Cellulose not digested by humans.

b. the storage form of carbohydrates in plants is starch

C amylose contains 1-4 glycosidic bond

D Glycogen and starch are highly branched polysaccharides.

Explanation:

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2 years ago
What is the most common substance found in natural gas
kifflom [539]
Methane composes most of the natural gas.
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3 years ago
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In what direction does energy move​
Arlecino [84]

In every direction guyz but conventionally it moves from higher potential to lower potential

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What is a criterion for all products made using the process of technological design? The product must be cheaper than similar pr
Galina-37 [17]

Answer:

C. The product must solve the problem for which it was designed.

Explanation:

Technological design is the study, development and application of technological process with the intent of designing a product to solve required problem.The process could be based on the use of a computer.

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8 0
3 years ago
Hydrofluoric acid and Water react to form fluoride anion and hydronium cation, like this HF(aq) + H_2O(l) rightarrow F(aq) + H_3
maksim [4K]

Answer:

Kc = 1.09x10⁻⁴

Explanation:

<em>HF = 1.62g</em>

<em>H₂O = 516g</em>

<em>F⁻ = 0.163g</em>

<em>H₃O⁺ = 0.110g</em>

<em />

To solve this question we need to find the moles of each reactant in order to solve the molar concentration of each reactan and replacing in the Kc expression. For the reaction, the Kc is:

Kc = [H₃O⁺] [F⁻] / [HF]

<em>Because Kc is defined as the ratio between concentrations of products over reactants powered to its reaction coefficient. Pure liquids as water are not taken into account in Kc expression:</em>

<em />

[H₃O⁺] = 0.110g * (1mol /19.01g) = 0.00579moles / 5.6L = 1.03x10⁻³M

[F⁻] = 0.163g * (1mol /19.0g) = 0.00858moles / 5.6L = 1.53x10⁻³M

[HF] = 1.62g * (1mol /20g) = 0.081moles / 5.6L = 0.0145M

Kc = [1.03x10⁻³M] [1.53x10⁻³M] / [0.0145M]

<h3>Kc = 1.09x10⁻⁴</h3>
7 0
3 years ago
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