Answer:
a) t = 4.14 s
b) Speed with which it hits the ground = 40.58 m/s
Explanation:
Using the equations of motion,
g = 9.8 m/s², y = H = 84 m,
Initial velocity, u = 0 m/s,
final velocity, v = ?
Total Time of fall, t = ?
a) y = ut + gt²/2
84 = 0 + 9.8t²/2
4.9t² = 84
t² = 84/4.9
t = 4.14 s
b) v = u + gt
v = 0 + (9.8 × 4.14)
v = 40.58 m/s
Answer:
Speed of the car, v = 8.90 m/s
Explanation:
It is given that,
The centripetal acceleration experienced by the car,
Diameter of the circle, d = 27 m
Radius of the circle, r = 13.5 m
The centripetal acceleration is experienced by an object if it moves in a circular path. The formula for the centripetal acceleration is given by :
v = 8.90 m/s
So, the maximum speed of the car in this roundabout is 8.9 m/s. Hence, this is the required solution.
Answer:
The value is
Explanation:
From the we are told that
The radius of the sphere is
The temperature is
The average temperature of the rest of the universe is
Generally the change in entropy of the entire universe per second is mathematically represented as
Here is the entropy of the rest of the universe which is mathematically represented as
Here Q is the quantity of heat radiated by the star which is mathematically represented as
Here is the Stefan-Boltzmann constant with value
=>
=>
So
=>
Here is the entropy of the rest of the universe which is mathematically represented as
=>
=>
So
=>
Answer:
35 N to the right
Explanation:
When calculating net force when both forces are on the same side you add them when they are going against each other you subtract them.
Answer
given,
mass of ball, m = 57.5 g = 0.0575 kg
velocity of ball northward,v = 26.7 m/s
mass of racket, M = 331 g = 0.331 Kg
velocity of the ball after collision,v' = 29.5 m/s
a) momentum of ball before collision
P₁ = m v
P₁ = 0.0575 x 26.7
P₁ = 1.535 kg.m/s
b) momentum of ball after collision
P₂ = m v'
P₂ = 0.0575 x (-29.5)
P₂ = -1.696 kg.m/s
c) change in momentum
Δ P = P₂ - P₁
Δ P = -1.696 -1.535
Δ P = -3.231 kg.m/s
d) using conservation of momentum
initial speed of racket = 0 m/s
M u + m v = Mu' + m v
M x 0 + 0.0575 x 26.7 = 0.331 x u' + 0.0575 x (-29.5)
0.331 u' = 3.232
u' = 9.76 m/s
change in velocity of the racket is equal to 9.76 m/s