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4 years ago

A car engine applies a force of 65 kN how much work is done by the engine as it pushed a car distance of 75m?

Physics

1 answer:

Artemon [7]4 years ago

3 0

The mathematical definition of work is simply the product of force and distance. That is:

Work = Force * Distance

Hence the work done here by the engine is:

Work = 65 kN * 75 m

Work = 4,875 kJ

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3 years ago

For the winter, a duck flies 10.0 m/s due south against a gust of wind with a velocity of 2.5 m/s. What is the resultant velocit

maria [59]

Answer:

c. 7.5 m/s south

Explanation:

Given the following data;

Velocity of duck = 10m/s due South

Velocity of wind = 2.5m/s

To find the resultant velocity;

Since we know that the duck is flying against a gust of wind, we would have to subtract the velocity of the gust of wind from that of the duck.

This ultimately implies that, the gust of wind (headwind) would decrease the resulting velocity of the duck because it approaches the duck from the front.

Resultant velocity, /V/ = 10 - 2.5

Resultant velocity, /V/ = 7.5m/s South.

Therefore, the resultant velocity of the duck is 7.5m/s south.

6 0

3 years ago

If a train is travelling 200km/hour eastward for 1800 seconds how far does it travel?

Olenka [21]

Answer:

Distance, d = 99990 meters

Explanation:

It is given that,

Speed of the train, v = 200 km/h = 55.55 m/s

Time taken, t = 1800 s

Let d is the distance covered by the train. We know that the speed of an object is given by total distance covered divided by total time taken. Mathematically, it is given by :

$v=\dfrac{d}{t}$

$d=v\times t$

$d=55.55\times 1800$

d = 99990 m

So, the distance covered by the train is 99990 meters. Hence, this is the required solution.

5 0

3 years ago

One star has a temperature of 30,000 K and another star has a temperature of 6,000 K. Compared to the cooler star, how much more

Lilit [14]

Answer:

The hotter star radiates 625 times more energy per second from each square meter of its surface

Explanation:

Temperature of the hotter star is 30000 K

temperature of the cooler star = 6000 K

From Stefan-Boltzmann radiation laws, for a non black body

P = εσA $T^{4}$

where

P is the energy per second or power of radiation

ε is the emissivity of the body

σ is the Stefan-Boltzmann constant of proportionality

A is the area of the sun

T is the temperature of the sun

The sun can be approximated as a black body, and the equation reduces to

P = σA $T^{4}$

For the hotter body,

P = σA( $30000^{4}$ ) = 8.1 x 10^17σA J/s

For the cooler body,

P = σA( $6000^{4}$ ) = 1.296 x 10^15σA J/s

comparing the two stars energy

==> (8.1 x 10^17)/(1.296 x 10^15) = 625

This means that the hotter star radiates 625 times more energy per second from each square meter of its surface

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3 years ago

In two or more complete sentences, explain how you can prove that the number of degrees that the Moon rotates around the Earth e

PolarNik [594]

Answer:

Follows are the explanation to this question:

Explanation:

In this solution, it is defined that there are two principal motions for the moon, which are its revolution as well as rotation. In such a movement called revolution, its Moon is relocating around the Earth, in which the approximate movement of the moon from around earth has an average movement of about 13.2° per day, or 92 degrees every week, that's once in 27.3 days.

3 0

3 years ago

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