1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
NARA [144]
3 years ago
14

If 655j are added to ethanol (grain alcohol) and its temperature rises from 18.2 C to 32.8 C, what is the mass of the ethanol sa

mple?
Chemistry
1 answer:
WARRIOR [948]3 years ago
5 0
G= 6.96 kcal/g is the answer to the question


You might be interested in
Select the sentence from the section "Cute Beavers Also Cause Trouble" that is MOST important to include in the section's summar
vichka [17]

The section "Cute Beavers Also Cause Trouble" that is MOST important to include in the section's summary is They can also be moved or killed if they cause trouble.

<h3>Are beavers a threat to humans?</h3>

Beavers are not to be creature which are not dangerous if left to be alone. But, they will often confront any threat when they are trapped or cornered, and thus a beaver will attack a human.

Hence, The section "Cute Beavers Also Cause Trouble" that is MOST important to include in the section's summary is They can also be moved or killed if they cause trouble.

Learn more about Beavers from

brainly.com/question/26756213

#SPJ1

5 0
2 years ago
Identify the reactants in the equation: 6C0, + 6H2O - CHUO+ 60,
Effectus [21]

Answer:

The correct answer is d. 6H20 + 6CO2.

The reactant in the chemical reaction 6H2O + 6CO2 ---> C6H12O6 + 6O2 is 6H20 + 6CO2. Remember that the reactant is always at the left side of the equation. So the correct answer is 6H20 + 6CO2 since it's in the left of the equation. I hope this answer helped you.

Explanation:

5 0
3 years ago
1. What is the molarity of a solution which contains 0.256 mol of a substance dissolved in 143 mL of solution.
LenaWriter [7]

Answer:

The equation for molarity is moles/liter for the first question you would do 0.256/0.143 liters to get 1.790 mol/L

Explanation:

The second problem you would do need to find the moles of NaCl which you would do by doing 4.89 g/58.44g/mol= 0.08367 then do 0.08367/0.600= 0.139 mol/L

The third problem would be the same steps as the second one.

The fourth problem would be (0.460M)(5.50L)= 2.53 moles

4 0
3 years ago
If 5.100 g of c6h6 is burned and the heat produced from the burning is added to 5691 g of water at 21 °c, what is the final temp
emmasim [6.3K]
  <span>C6H12 = 6x12 + 6x1 = 78. 
The equation indicates that 2x78 = 156g benzene will produce 6542kJ. 
Using proportions you can then calculate that 
x/6542kJ = 7.9g / 156g 
x = 331.3kJ = 331300J. 

heat = mass x ΔT x 4.18J/g° 
ΔT = 331300J / (5691g x 4.18J/g°) = 13.9° 

final temp = 21 + 14° = 35°C</span>
4 0
4 years ago
What is the bonding requirement for carbon atoms?
Artyom0805 [142]

Answer:

carbon atoms tend to make four bonds, each carbon atom will have the number of hydrogen atoms that are required for four bonds. This compound contains 16 hydrogen atoms for a molecular formula of C 8 H 16.

Explanation:

7 0
2 years ago
Other questions:
  • What is the solubility of 2 kilograms of potassium chloride (KCl) dissolved into 750 cm3 of water? A. 0.375g/dm3 B. 1500g/dm3 C.
    13·1 answer
  • Please help with my 1.11 asignment and you get 20 points
    14·1 answer
  • All of the following statements concerning voltaic cells are true EXCEPT
    9·1 answer
  • NO<br> Assign oxidation numbers to each element in this compound.
    9·1 answer
  • Both the volcano and the seamount chain are thought to be the result of
    12·1 answer
  • Complete the nuclear reaction.*
    6·1 answer
  • What is a better indicator in the titration of HCl with Na2CO3, methyl orange or methyl red, and why​
    12·1 answer
  • I need helpppp plzzzz
    10·1 answer
  • 1:( Que estudia la química ?
    14·1 answer
  • I got some chemistry for yall
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!