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8_murik_8 [283]
3 years ago
7

12х - 5 >3х^2 +5 I am confused how to solve this.

Mathematics
1 answer:
Agata [3.3K]3 years ago
6 0

Answer (3 different forms):

<u>1st Form:</u>

2+-\frac{1}{3} \sqrt{6}

<u>2nd Form:</u>

-\sqrt\frac{2}{3}+2

<u>3rd Form:</u>

\frac{6-\sqrt{6}}{3}

Or

(\frac{6-\sqrt{6}}{3}),(\frac{6+\sqrt{6}}{3})

Step-by-step explanation:

You can see that I put three different forms of answers, but they are all still equivalent answers. The reason why I got three different answers is because I put the inequality in three different calculators and they all got me different answers, but all three are still equivalent. The following three attachments are images of the three calculators that I used to solve.

Hope this helps and answers your question! :)

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Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 1500, \sigma = 300

Find the limit that 97.5% of the data points will be above.

This is the value of X when Z has a pvalue of 1-0.975 = 0.025. So it is X when Z = -1.96.

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X = 912

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