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Jlenok [28]
3 years ago
10

Ronald has a candy mixture. It has brown chocolate pieces and various colored hard candy pieces. All the candy pieces are the sa

me shape, size, and weight. What physical properties could be used to separate these mixtures? Select all that apply.
A.

color
B.

weight
C.

shape
D.

magnetism
E.

melting point
Chemistry
1 answer:
Keith_Richards [23]3 years ago
8 0

Answer:

A and E for sure.

Explanation:

Can't be B or C, since it is stated in the problem. And probably not D because candy don't have magnetism to them.

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seraphim [82]
Should be all of the above (A)
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3 years ago
Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction
inessss [21]

Answer:

Explanation:

2 NH4I    + Pb(NO3)2   =  PbI2  + 2 NH4NO3

2 mol          1 mol

x ml             751 ml

0.550 M      0.380 M

0.380 mol/1000 ml  x 751 ml =  0.285 mol Pb(NO3)2

0.285 mol Pb(NO3)2 x 2 mol NH4I/1 mol  Pb(NO3)2=0.571 mol  NH4I  needed

0.571 mol  NH4I/0.550 mol/1000 ml=1038 ml

6 0
3 years ago
What mass of boron sulfide must be processed with 2.1 x 10 4g of carbon to yield 3.11 x 10 4 g of boron and 1.47 x 10 5 g of car
Basile [38]

The reaction between boron sulfide and carbon is given as:

2B2S3 + 3C → 4B + 3CS2

As per the law of conservation of mass, for any chemical reaction the total mass of reactants must be equal to the total mass of the products.

Given data:

Mass of C = 2.1 * 10^ 4 g

Mass of B = 3.11*10^4 g

Mass of CS2 = 1.47*10^5

Mass of B2S3 = ?

Now based on the law of conservation of mass:

Mass of B2S3 + mass C = mass of B + mass of CS2

Mass of B2S3 + 2.1 * 10^ 4 = 3.11*10^4 + 1.47*10^5

Mass of B2S3 = 15.7 * 10^4 g


4 0
4 years ago
Sodium carbonate (Na2CO3) reacts with acetic acid (CH3COOH) to form sodium acetate (NaCH3COO), carbon dioxide (CO2), and water (
trapecia [35]
Use the formula q=m×Cp×delta T

m=1.500 kg=1,500 g
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delta T=0.985k

q=(1,500g)(2.52 J/g·k)(0.985k)

=3,723.3 J=3.72


I JUST FINISHED THIS QUESTION AND IT SAID THAT THE ANSWER WAS -3.72 kJ SO PUT THAT DOWN AS YOUR ANSWER....I'm not sure why the answer is negative, but this is the most work I can show. If any one knows, why this answer is negative, please advise. Thank you. I hope that this helps :)
7 0
3 years ago
Read 2 more answers
Four gases were combined in a gas cylinder with these partial pressures: 3.5 atm N2, 2.8 atm O2, 0.25 atm Ar, and 0.15 atm He. W
liq [111]

The total pressure is 6.7 atm.  The mole fractions of O₂ and Ar are 0.42 and 0.037.

<em>p</em>(Tot) = <em>p</em>(N₂) + <em>p</em>(O₂) + <em>p</em>(Ar) + <em>p</em>(He) = 3.5 atm + 2.8 atm + 0.25 atm + 0.15 atm = 6.7 atm

χ(O₂) = p(O₂)/p(Tot) = 2.8 atm/6.7 atm = 0.42

χ(Ar) = p(Ar)/p(Tot) = 0.25 atm/6.7 atm = 0.037

6 0
4 years ago
Read 2 more answers
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