Answer:
The concentration in mol/L is 0.683M
Explanation:
23.5% (w/w)
This data means that in 100 g of solution, we have 23.5 grams of solute.
From this point, we can calculate the moles of sugar.
Moles = Mass / Molar mass
Moles = 23.5 g /342.30 g/m
Moles = 0.068 moles
Density data make us know, the volume of our solution.
solution δ = solution mass / solution volume
δ = 1.005 g/mL = 100 g / solution volume
solution volume = 100g / 1.005 g/ml
solution volume = 99.5 mL
In conclusion, 0.068 moles are in 99.5 mL
Molarity (M) is mol/L
Let's convert 99.5 mL in L
99.5 mL / 1000 = 0.0995 L
0.068 m / 0.0995L = 0.683
<em>If we convert moles in mmoles, we can also get Molarity (M)</em>
<em>mmoles / mL = M</em>
<em>0.068 moles . 1000 = 68 mmoles</em>
<em>68 mmmoles / 99.5mL = 0.683</em>
