Answer:
The probability that an 18-year-old man selected at random is greater than 65 inches tall is 0.8413.
Step-by-step explanation:
We are given that the heights of 18-year-old men are approximately normally distributed with mean 68 inches and a standard deviation of 3 inches.
Let X = <u><em>heights of 18-year-old men.</em></u>
So, X ~ Normal(
)
The z-score probability distribution for the normal distribution is given by;
Z =
~ N(0,1)
where,
= mean height = 68 inches
= standard deviation = 3 inches
Now, the probability that an 18-year-old man selected at random is greater than 65 inches tall is given by = P(X > 65 inches)
P(X > 65 inches) = P(
>
) = P(Z > -1) = P(Z < 1)
= <u>0.8413</u>
The above probability is calculated by looking at the value of x = 1 in the z table which has an area of 0.8413.
Answer:
84
Step-by-step explanation:
Answer: option d. x = 3π/2Solution:function y = sec(x)
1) y = 1 / cos(x)
2) When cos(x) = 0, 1 / cos(x) is not defined
3) cos(x) = 0 when x = π/2, 3π/2, 5π/2, 7π/2, ...
4) limit of sec(x) = lim of 1 / cos(x).
When x approaches π/2, 3π/2, 5π/2, 7π/2, ... the limit →+/- ∞.
So, x = π/2, x = 3π/2, x = 5π/2, ... are vertical asymptotes of sec(x).
Answer: 3π/2
The figures attached will help you to understand the graph and the existence of multiple asymptotes for y = sec(x).