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3 years ago

PLS HELP Find the value of x. A. 4 B. 2 C. 7 D. 14

Mathematics

2 answers:

likoan [24]3 years ago

5 0

Answer:

B. 2

Step-by-step explanation:

The sides 5x - 3 and 3x + 1 are the same length, so you can put an equal sign: 5x - 3 = 3x + 1, x = 2:

5(2) - 3 = 3(2) + 1

10 - 3 = 6 + 1

7 = 7

So x is 2

mars1129 [50]3 years ago

4 0

Answer:

ANSWER IS B

Step-by-step explanation:

5x - 3 = 3x + 1

5x - 3x = 1 + 3

2x = 4

x = 4/2

x = 2

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Yuliya22 [10]

Answer:

D. f(-3) = 11

Step-by-step explanation:

When f(x) is divided by x+3, you get a quotient g(x) and a remainder of 11:

f(x) / (x + 3) = g(x) + 11 / (x + 3)

Multiply both sides by x+3:

f(x) = g(x) (x + 3) + 11

Substitute -3 for x:

f(-3) = g(-3) (-3 + 3) + 11

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3 years ago

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olya-2409 [2.1K]

Answer:

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Step-by-step explanation:

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8 0

3 years ago

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What are the solutions to the following system? StartLayout Enlarged left-brace 1st row negative 2 x squared + y = negative 5 2n

Yakvenalex [24]

Answer:

$(\sqrt{2},-1),(-\sqrt{2},-1)$

(StartRoot 2 EndRoot, negative 1) and (negative StartRoot 2 EndRoot, negative 1)

Step-by-step explanation:

we have

$-2x^{2} +y=-5$ ----> equation A

$y=-3x^{2} +5$ -----> equation B

solve by substitution

substitute equation B in equation A

$-2x^{2} +(-3x^{2} +5)=-5$

solve for x

$-5x^{2} +5=-5$

$-5x^{2}=-10$

$x^{2}=2$

$x=\pm\sqrt{2}$

Find the value of y

$y=-3x^{2} +5$

For $x=\sqrt{2}$ ----> $y=-3(\sqrt{2})^{2} +5=-1$

For $x=-\sqrt{2}$ ----> $y=-3(-\sqrt{2})^{2} +5=-1$

therefore

The solutions are

$(\sqrt{2},-1),(-\sqrt{2},-1)$

(StartRoot 2 EndRoot, negative 1) and (negative StartRoot 2 EndRoot, negative 1)

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4 years ago

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irina1246 [14]

Answer: V ( t ) = 1 + 1 4 e − 0 . 1 0 4 t 1 5 , 0 0 0 

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3 years ago

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Travka [436]

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ANSWER: C.

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2 years ago

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