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ZanzabumX [31]
2 years ago
15

Pleas I need help ASAP

Mathematics
2 answers:
Travka [436]2 years ago
5 0

NOTE: sorry if im wrong

ANSWER: C.

Luda [366]2 years ago
5 0

Answer:

a)

c)

d)

Step-by-step explanation:

a) true : from inspection of the graph, when h=0, g=50, so g(0)=50

b) false : we are told that h is hours after 8:00am.  Therefore, when h=12, this would be 8:00pm

c) true : from inspection of the graph, the maximum temperature occurs when h=7. We are told that h is hours after 8:00am, so when h=7 this would be 15:00 = 3.00pm

d) true : from inspection of the graph, we can see that when h=11, g≈62 and when h=8, g≈74.  Therefore g(11) < g(8)

e) false : at 8.00am, h=0 and g=50.  At 1.00pm, h=5 and g≈71.  71-50=21.  21≠10.

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PLEASE I need help on these 4 problems you don’t have to do them all but if you can at least do one of them TYSM
Brrunno [24]

Answer:

For right angle triangle,

we use Pythagoras theorem that is:

c^{2} =a^{2} +b^{2}

c = \sqrt{a^{2} +b^{2} }

For question 1:

c = ?

a = 40

b = 9

putting them in formula,

c = \sqrt{40^{2} + 9^{2} }

c = 41

For question 2:

c = ?

a = 12

b = 13

putting them in formula,

c = \sqrt{12^{2} + 13^{2} }

c = approximately 17.69181

For question 3:

c = 35

a = 20

b = ?

putting them in formula,

c^{2} =a^{2} +b^{2}

35^{2} = 20^{2} + b^{2}

1225 = 400 + b^{2}

b^{2} = 1225 - 400

b^{2} = 825

\sqrt{b^{2} } = \sqrt{825}

b = 5 \sqrt{33}

For question 4:

c = 37

a = 20

b = ?

putting them in formula,

c^{2} =a^{2} +b^{2}

37^{2} = 20^{2} + b^{2}

1369 = 400 + b^{2}

b^{2} = 1369 - 400

b^{2} = 969

Taking square root on both sides

b = 31.12

Hope it helps.

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2 years ago
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