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Yuri [45]
3 years ago
15

Helpppppppppppp.......!

Physics
1 answer:
Black_prince [1.1K]3 years ago
3 0

Explanation:

m = 66 kg

a = 2 m/s²

F = .....?

<h3>F = m . a</h3>

= 66 . 2

= 132 N

<h3>#CMIIW</h3>

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The space shuttle fleet was designed with two booster stages. if the first stage provides a thrust of 53 kilo-newtons and the sp
lidiya [134]

To solve this problem we will apply Newton's second law, which indicates that the force is equivalent to the product between mass and acceleration, so

F = ma

Here,

F= Force

m = Mass

a = Acceleration

Rearranging to find the mass we have,

m = \frac{F}{a}

The value of the acceleration is

a = 18miles/hour^2 (\frac{0.00012417m/s^2}{1 miles/hour^2})

a = 0.002235m/s^2

Replacing to find the mass,

m = \frac{53kN}{0.002235m/s^2}

m = \frac{53*10^{-3}}{0.002235}

m = 23.71kg

Now in ponds this value is

m = 23.71kg(\frac{2.205lb}{1kg})

m=52.8 lb

Therefore the mass of the spacecraft is 52.8lb

4 0
2 years ago
A car is moving with 15000J of energy. If the car has a mass of 1500kg, how fast is it moving?
Arte-miy333 [17]

Answer:

V=4.5 m/s

Explanation:

KE=1/2mv^2

1500=1/2(15000)v^2

6 0
2 years ago
10. Suppose the tern travels 1.70*10^ km south, only to encounter bad weatherInstead of trying to fly around the stormthe tem tu
Ghella [55]

We can define average speed as the quotient between the whole distance traveled and the time it takes to travel that distance, and the velocity as the quotient between the displacement and the time it takes to displace that quantity.

We will find that:

Average speed =  2.6×10^2 km/day

Velocity = 2.52×10^2 km/day

So we know that:

The tent travels:

1.70×10^4 km to the south

6.00×10^2 km to the north

1.44×10^4 km to the south.

The total distance traveled is just the sum of the 3 above distances:

total distance = 1.70×10^4 km +  6.00×10^2 km + 1.44×10^4 km

Notice that the second term has a different exponent than the others, so to have the same exponent we can write:

6.00×10^2 km = 0.06×10^4 km

Now we get:

total distance = 1.70×10^4 km + 0.06×10^4 km + 1.44×10^4 km

total distance = (1.70 + 0.06 + 1.44)×10^4 km

<u>total distance = 3.2×10^4 km</u>

And it travels that distance in 122 days, then the average speed is:

AS = (3.2×10^4 km)/(122 days) = 2.6×10^2 km/day

Now we need to find the displacement, which is the difference between the final position and the initial position, the displacement will just be:

d =  1.70×10^4 km - 0.06×10^4 km + 1.44×10^4 km

(We add the distance traveled to south and subtract the distance that it travels due north)

d = (1.70 - 0.06 + 1.44)×10^4 km = 3.08×10^4 km

Then the velocity will be:

v = (3.08×10^4 km)/(122 days) = 2.52×10^2 km/day

Because we defined south as positive and north as negative, having a positive velocity means that the direction of the <u>velocity is due south.</u>

If you want to learn more, you can read:

brainly.com/question/12322912

 

3 0
2 years ago
A 500N person stands 2.5m from a wall against which a horizontal beam is attached. The beam is 6m long and weighs 200N. A cable
Vinil7 [7]

PART A)

Here by force balance along Y direction

Tsin45  + F_y = 500 + 200

Force balance along X direction

Tcos45 = F_x

now by torque balance

Tsin45 (6) = 500 (2.5) + 200 (3)

T(4.24) = 1250 + 600

T = 436.3 N

PART B)

now from above equations

Tsin45 + F_y = 700

F_y = 391.5 N

F_x = Tcos45 = 308.5 N

now net reaction force of wall is given as

F = \sqrt{F_x^2 + F_y^2}

F = 498.4 N

5 0
3 years ago
After you enlarge a map, which one of the following scale remains correct?
9966 [12]

Answer:

None

Explanation:

An scale is the factor by which actual features on ground are enlarged or reduced for representing on a plane. There are different kinds of scales:

  • Verbal scale use of words to represent scale information on the map.  The distance or linear units are used for depicting this scale on the map.  For example: 1 inch = 1 Kilo meter.
  • Fractional scale uses the numbers or values for showing the scale instead of words. As the name says, it is represented using a fraction or ratio.  Example: 1: 10,000 or 1/10,000
  • In large scale more details are shown in a map, however, less area coverage will be shown in a single map as the scale is large and more details are given.  Example: 1:500
  • Small scale is exactly opposite to the large scale, less details are shown as magnification is not enough, however a large amount of area can be shown in a single map.  Example: 1:25,000
  • A graphic scale is a bar that has been calibrated to show map distances. On maps that have been reduced or enlarged the original ratio and written scales are incorrect, since the relationship between map distance and real world distance has been altered, graphic scale is enlarged or reduced to the same extent as the map, this makes it the right option.

I hope you find this information useful and interesting! Good luck!

6 0
3 years ago
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