Consider a person sliding down a water slide at constant velocity. what are the forces acting on the person as they slide? are t
he forces balanced or unbalanced? explain.
2 answers:
Explanation :
When a person is sliding with constant velocity, the forces that are acting on him are :
(1) Weight, W = mg where g is acceleration due to gravity.
(2) Friction forces acting opposite to the direction of motion.
(3) Normal force.
The forces acting on the person is balanced because the person is sliding with constant velocity.
From figure it is clear that, friction force is balanced by and normal is balanced by
.
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Answer:
a)η = 69.18 %
b)W= 1210 J
c)P=3967.21 W
Explanation:
Given that
Q₁ = 1749 J
Q₂ = 539 J
From first law of thermodynamics
Q₁ = Q₂ +W
W=Work out put
Q₂=Heat rejected to the cold reservoir
Q₁ =heat absorb by hot reservoir
W= Q₁- Q₂
W= 1210 J
The efficiency given as
η = 69.18 %
We know that rate of work done is known as power
P=3967.21 W
Here you go it was too long to type
Answer:
The burden distance is 7 ft
Solution:
As per the question:
Specific gravity of package emulsion,
Specific gravity of diabase rock,
Diameter of the packaged sticks, d = 3 in
Now,
To calculate the first trail shot burden distance, B:
B = 7 ft