Answer:
121.43 m
Explanation:
Solution
Since standing waves are set up, the expression for the first mode of frequency is f₁ = nv/4L. The next mode of frequency is f₂ = (n + 2)v/4L where L is the length of the tunnel and v the speed of sound. f₁ = 5.0 Hz, f₂ = 6.4 Hz, v = 340 m/s. We now subtract f₂ - f₁ = (n + 2)v/4L - nv/4L = v/2L.
So f₂ - f₁ = v/2L. and L = v/2(f₂ - f₁) = 340/[2× (6.4-5.0)] = 340/2×1.4 = 340/2.8 = 121.43 m
So, it is 121.43 m far to the end of the tunnel.
SO my sports name would be called " Basvollball" It's where you have to hit in a volleyball into a basketball hoop, of course, the time is the same as football with increments of 5 minutes for junior high and 7 minutes for high school with halftime. Also, the ball can never touch the ground and if the ball ever hits the floor its the other's team ball. To decide which team gets the ball, a coin flip will decide it. For the point system, it depends on how far the ball is hit from so it's like basketball from 3 pointers to 2 points inside the line. If the team ever reaches 30 points without the other team scoring, the team who's winning will automatically win after the time runs out in that period or quarter. You can use every body part, as long as, the ball doesn't touch the floor, and you can only use your body to push someone, no pushing with hands or arms. You can play this sport indoors or outside whether the team has a field available. There's also a maximum of 14 players on the field, so 7 players on each team.
Answer:
0.00321 Nm
Explanation:
= Final angular velocity = 3.5 rad/s
= Initial angular velocity = 0
= Angular acceleration
= Angle of rotation = 2 rev
Equation of rotational motion
Moment of inertia is given by
Torque is given by
The torque required is 0.00321 Nm
Answer:
Total work done = 15,306.25 lb.ft
Explanation:
First of all, we know that;
Work done = Force x Distance.
Thus,
Work done to pull bucket (Wb) = 500 x 30 = 15,000 lb.ft
Now, work done by pulling the rope is given as a function of the length of the rope. Thus;
Wr =(x,x=0∫) F(x) dx
=(35,0∫) 0.5x dx
= 0.5[x²/2](35,0)
Thus,Wr = 0.5[(35²/2) - (0²/2)] = 0.5[612.5] = 306.25 lb.ft
Total work done will be the sum of that done to pull the bucket and that done to pull the rope.
Thus, Wt = Wb + Wr
Wt = 15000 + 306.25 = 15,306.25 lb.ft
Answer:
The ratio of momentum is 1:2 since the velocity is constant and mass is of ratio 1:2
Explanation:
Given
mass of car = 500 kg
mass of truck = 1000 kg
velocity of car = velocity of truck = v = 5 m/s
momentum of car = ?
momentum of truck = ?
We know that the momentum is given by: p = mv , where m is mass and v is velocity.
momentum of car = x v = 500 x 5 = 2500 kg.m/s
momentum of truck = x v = 1000 x 5 = 5000 kg.m/s
The ratio of momentum =
=
= = 1:2
Here we infer that the ratio is 1:2. This is because momentum value depends on mass and velocity of body. In given problem velocity is constant. Hence depends only on mass. The ratio of mass is 1:2 and so the ratio of momentum.