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4 years ago

Type the correct answer in the box.

Physics

1 answer:

algol [13]4 years ago

4 0

Answer:

3 m/s

Explanation:

12m/s increase

acceleration is 3m/s

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Denis throws a ball downward at an initial speed of 15 m/s from the top of a cliff. (a)

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Multiply the time by the acceleration due to gravity to find the velocity when the object hits the ground. If it takes 9.9 seconds for the object to hit the ground, its velocity is (1.01 s)*(9.8 m/s^2), or 9.9 m/s.

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3 years ago

n astronaut who weighs 800 N on the surface of the earth lifts off from planet Zuton in a space ship. The free-fall acceleration

ANTONII [103]

Answer: 0.29 kN

Explanation:

We have the following data:

$W_{E}=800 N$ is the weight of the astronaut on Earth

$g_{E}=9.8 m/s^{2}$ is the free fall acceleration due gravity on Earth (directed downwards)

$g_{Z}=3 m/s^{2}$ is the free fall acceleration due gravity on Zuton (directed downwards)

$a=0.5 m/s^{2}$ is the acceleration of the spaceship at litoff (directed upwards)

We have to find the <u>magnitude of the force</u> $F$ the space ship exerts on the astronaut.

Firstly, we have to know weight has a direct relation with the mass and the acceleration due gravity. In the case of Earth is:

$W_{E}=mg_{E}$ (1)

Where $m$ is the mass of the atronaut.

Isolating $m$ :

$m=\frac{W_{E}}{g_{E}}$ (2)

$m=\frac{800 N}{9.8 m/s^{2}}$ (3)

$m=81.63 kg$ (4)

Now that we know the mass of the astronaut, we can find its weight on Zuton:

$W_{Z}=mg_{Z}$ (5)

$W_{Z}=(81.63 kg)(3 m/s^{2})$ (6)

$W_{Z}=244.89 N$ (7)

Then, we can calculate the force the space ship exerts on the astronaut by the following equation:

$F-W_{Z}=m.a$ (8)

Isolating $F$ :

$F=m.a+W_{Z}$ (9)

$F=(81.63 kg)(0.5 m/s^{2})+244.89 N$ (10)

$F=285.7 N \frac{1 kN}{1000 N}=0.285 kN$ (11)

Finally:

$F=0.285 kN \approx 0.29 kN$

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