A heat engine does 9200 J of work per cycle while absorbing 22.0 kcal of heat from a hightemperature reservoir. What is the effi
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Answer:
change in internal energy 3.62*10^5 J kg^{-1}
change in enthalapy 5.07*10^5 J kg^{-1}
change in entropy 382.79 J kg^{-1} K^{-1}
Explanation:
adiabatic constant
specific heat is given as
gas constant =287 J⋅kg−1⋅K−1
specific heat at constant volume
change in internal energy
change in enthalapy
change in entropy