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Serhud [2]
2 years ago
11

An object weighing 2.7n while in air and 1.2n when completely immersed in water.find the relative density of the object

Physics
1 answer:
Elden [556K]2 years ago
8 0

Answer:

1.8 = relative density (there are no units for relative density)

Explanation:

It displaces water equal to it's volume and gets buoyancy equal to that amount of water

2.7 - 1.2  = 1.5  N  of buoyancy

density of water = 1 gm /cc

 1.5 N = m (9.81)

    m of water displaced = .1529 kg

             152.9 cc of water will produce this buoyancy....this is the volume of the object

   

find mass of object     2.7 = m (9.81)     shows m = .2752 kg = 272.5 gm

density = mass/ volume = 272.5 / 152.9 = 1.8 gm / cc

Relative to water (which is 1 gm / cc) the relative density is 1.8

  ====> it is 1.8 times denser than water and will sink when in water....

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Answer:

The approximate combined sound  intensity is I_{T}=1.1\times10^{-4}W/m^{2}

Explanation:

The decibel  scale intensity for busy traffic is 80 dB. so intensity will be

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In the same way for the loud conversation having a decibel intensity of 70 dB.

10log(\frac{I_{2}}{I_{0}} )=70, therefore I_{2}=1\times10^{7}I_{0}=1\times10^{7} * 1\times10^{-12}W/m^{2}=1\times10^{-5}W/m^{2}

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The answer to the question is false. Hope this helps you!

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