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3 years ago

Find the seventh term of each sequence 1, -3, 9, -27.....

Mathematics

1 answer:

LenaWriter [7]3 years ago

6 0

multilply by negative three to find the next term. 1, -3, 9, -27, 81, -243, 729, which is the seventh term.

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Q(x)= 1/2x - 3; q(x) =-4. Find the value of x

Lelu [443]

Answer:

$q(x) =-5$

Step-by-step explanation:

I am solving this using Function Notation.

We are given:

$q(x)= \frac{1}{2}x - 3$

While we are to find:

$q(x) =-4$

In Function Notation, replace all the " $x$ " you see with the value you are given.

So, in this case,

$q(x)= \frac{1}{2}x - 3\\\\=\frac{1}{2}x - 3$

Would become

$q(x)= \frac{1}{2}x - 3\\\\=\frac{1}{2}(-4) - 3$

Now we can solve.

$\frac{1}{2}(-4) - 3$

Use PEMDAS; Parenthesis first;

$\frac{1}{2}(-\frac{4}{1})$

Cross divide: 1 cancels 1, -4 ÷ 2 = -2

Hence, we are left with

$(-2) - 3$

$-5$

Therefore, the value of x is -5

8 0

2 years ago

I need help on this question 1/2x2x6

Alex

1/2x2x6
=1x6
=6
That's your answer.

3 0

3 years ago

For the function y=-1+6 cos(2pi/7(x-5)) what is the minimum value?

Ad libitum [116K]

Usually one will differentiate the function to find the minimum/maximum point, but in this case differentiating yields:
$\frac{2\pi}{7(x-5)^{2}}\sin{\frac{2\pi}{7(x-5)}}}$
which contains multiple solution if one tries to solve for x when the differentiated form is 0.

I would, though, venture a guess that the minimum value would be (approaching) 5, since the function would be undefined in the vicinity.

If, however, the function is
$-1+\cos{\frac{2\pi}{7}(x-5)}}$
Then differentiating and equating to 0 yields:
$\sin{\frac{2\pi}{7}(x-5)}}=0$
which gives:
$x=5$ or $8.5$

We reject x=5 as it is when it ix the maximum and thus,
$x=8.5\pm7n$ , for $n=0,\pm 1,\pm 2, ...$