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3 years ago

Why do engineers use math

1 answer:

4 0

Engineers use math because they have to calculate numbers together to know how much angle they will need when building and when they need to know how much wood/tools they need they have to use math to get those things.

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Please help!! I’m not sure how to answer this question!!

nlexa [21]

<h3>Answer: 9V</h3>

=============================================================

Reason:

The volume expression of a cone with radius r and height h is

$\frac{1}{3}\pi*r^2*h$

Let's plug in the given height h = 12 and we'd get

$\frac{1}{3}\pi*r^2*h\\\\\frac{1}{3}\pi*r^2*12\\\\\left(\frac{1}{3}*12\right)\pi*r^2\\\\4\pi*r^2\\\\$

This is the volume of the first cone. We're told the first cone has a volume of V, so we can say $V = 4\pi r^2$

We can't find the actual numeric volume because we don't know what value replaces r. So we leave it as is.

The second cone has the same height (h = 12) but the radius is now 3 times in size. Instead of r, we use 3r

Replace every copy of r with 3r. Then simplify

$4\pi*r^2\\\\4\pi*(3r)^2\\\\4\pi*9r^2\\\\9(4\pi r^2)\\\\9V\\\\$

The radius tripled which results in a volume that's 9 times bigger.

3 0

1 year ago

Select all the equations for which (-6,-1) is a solution. *

ella [17]

1 and 4 hope this helps!

8 0

3 years ago

13. A warehouse is distributing 1,080 blocks into 24 different packages for shipment. If each of the packages will hold the same

alina1380 [7]

Answer:

Step-by-step explanation:

All you have to do is 1080/24 that gives you 45.

8 0

2 years ago

10 POINTS! HELP ITS DUE SOON!!

Naddika [18.5K]

Answer:

Σ [n^2]

i=1

Step-by-step explanation:

Hope I helped? I inserted it into a calc and I also got 385 for something if its useful))

8 0

2 years ago

(6-3(cube root of 6)/(cube root of 9)

MatroZZZ [7]

For this case we must simplify the following expression:

$\frac {6-3 \sqrt [3] {6}} {\sqrt [3] {9}}$

Multiplying the numerator and denominator by $(\sqrt [3] {9}) ^ 2$

$\frac {6-3 \sqrt [3] {6}} {\sqrt [3] {9}} * \frac {(\sqrt [3] {9}) ^ 2} {(\sqrt [3] { 9}) ^ 2} =$

We rewrite:

$\frac {\frac {6-3 \sqrt [3] {6}} * (\sqrt [3] {9}) ^ 2} {\sqrt [3] {9} * (\sqrt [3] {9 }) ^ 2} =$

By properties of powers we have that:

$a ^ m * a ^ n = a ^ {m + n}\\\frac {(6-3 \sqrt [3] {6}) * (\sqrt [3] {9}) ^ 2} {(\sqrt [3] {9}) ^ 3} =\\\frac {(6-3 \sqrt [3] {6}) * (\sqrt [3] {9}) ^ 2} {9} =$