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emmasim [6.3K]
3 years ago
7

3D%20%20%7B%3F%7D%20%20%3A-%7D%7D%7D%7D%7D%20%5C%5C%20%20%5C%5C%20%7B%5Chuge%7B%5Cboxed%7B%7B%5Cred%7Bplease%20%5C%3A%20help%20%5C%3A%20%20%5C%3A%20%7D%7D%7D%7D%7D" id="TexFormula1" title="{\huge{\boxed{{\green{1 {}^{2} + 3 {}^{2} = {?} :-}}}}} \\ \\ {\huge{\boxed{{\red{please \: help \: \: }}}}}" alt="{\huge{\boxed{{\green{1 {}^{2} + 3 {}^{2} = {?} :-}}}}} \\ \\ {\huge{\boxed{{\red{please \: help \: \: }}}}}" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
Mnenie [13.5K]3 years ago
7 0

\huge \boxed{Answer \hookleftarrow}

=》1² + 3²

=》1 + 9

=》10

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What are the values for the coefficients and constant term of 0 = 2 + 3x2 – 5x?
tangare [24]

Keywords:

<em>Polynomial, variable, coefficients, constant term. </em>

For this case, the first thing we must do is rewrite the polynomial in a standard way. For this, we reorder the polynomial coefficients.

The standard form of the polynomial is:

ax ^ 2 + bx + c

Where,

a, b, c: are the coefficients of the polynomial.

x: is the variable

Rewriting the polynomial we have:

3x ^ 2-5x + 2

Comparing with the standard form we have that the values of the coefficients are given by:

a = 3\\b = -5\\c = 2

Answer:

The values for the coefficients and constant term are:

a = 3\\b = -5\\c = 2

4 0
3 years ago
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Here are the city gas mileages for 13 different midsized cars in 2008. 16, 15, 22, 21, 24, 19, 20, 20, 21, 27, 18, 21, 48 What i
Vaselesa [24]

Answer:

Q1 --> 18.5

Step-by-step explanation:

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2 years ago
Jessie is saving up for a purse that is $890. She gets $8 allowance per week, and already has $80 saved up. How long will it tak
LekaFEV [45]

Answer:

101.25 weeks

Step-by-step explanation:

890-80=810

810/8=101.25

8 0
3 years ago
A box contains 24 transistors,4 of which are defective. If 4 are sold at random,find the following probabilities. i. Exactly 2 a
zavuch27 [327]

SOLUTION

This is a binomial probability. For i, we will apply the Binomial probability formula

i. Exactly 2 are defective

Using the formula, we have

\begin{gathered} P_x=^nC_x\left(p^x\right?\left(q^{n-x}\right) \\ Where\text{ } \\ P_x=binomial\text{ probability} \\ x=number\text{ of times for a specific outcome with n trials =2} \\ p=\text{ probability of success = }\frac{4}{24}=\frac{1}{6} \\ q=probability\text{ of failure =1-}\frac{1}{6}=\frac{5}{6} \\ ^nC_x=\text{ number of combinations = }^4C_2 \\ n=\text{ number of trials = 4} \end{gathered}

Note that I made the probability of being defective as the probability of success = p

and probability of none defective as probability of failure = q

Exactly 2 are defective becomes the binomial probability

\begin{gathered} P_x=^4C_2\times\lparen\frac{1}{6})^2\times\lparen\frac{5}{6})^{4-2} \\ P_x=6\times\frac{1}{36}\times\frac{25}{36} \\ P_x=\frac{25}{216} \\ =0.1157 \end{gathered}

Hence the answer is 0.1157

(ii) None is defective becomes

\begin{gathered} \lparen\frac{5}{6})^4=\frac{625}{1296} \\ =0.4823 \end{gathered}

hence the answer is 0.4823

(iii) All are defective

\begin{gathered} \lparen\frac{1}{6})^4=\frac{1}{1296} \\ =0.00077 \end{gathered}

(iv) At least one is defective

This is 1 - probability that none is defective

\begin{gathered} 1-\lparen\frac{5}{6})^4 \\ =1-\frac{625}{1296} \\ =\frac{671}{1296} \\ =0.5177 \end{gathered}

Hence the answer is 0.5177

3 0
1 year ago
Factorize this term: (a+b)raise to the power of 4 +4
zimovet [89]

Answer:

<u>(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)</u>

Step-by-step explanation:

Given :

  • (a + b)⁴⁺⁴

Solving :

  • (a + b)⁸
  • <u>(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)</u>
8 0
2 years ago
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