1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dafna1 [17]
3 years ago
8

A cubic container has a height of 2 centimeters. What is the surface area of the cube?

Mathematics
1 answer:
monitta3 years ago
6 0

Answer:

Here IS Your ANSWER!⏬

its will be answer 8cm 2

HOPE THIS HELPED!

sorry if I'm Incorrect

You might be interested in
Can somebody help mee plzzzzzzzz
hammer [34]

Answer:

lines a and b are parallel. The slopes are -1/3

None of the lines are perpendicular to each other.

Step-by-step explanation:

To figure out if any of the lines are parallel or perpendicular to each other, you have to find the slopes of each line. To find the slope look at the graph find the rise over run for all of the lines:

line a: This line goes down one every time it goes over 3, which can be represented by -1/3

line b: This lines goes down one every time it goes over 3, which can also be written as -1/3

line c: This line goes up 5 every time it goes over 2, which makes the slope 5/2

When two lines are parallel, they have the same slope. Line a and line b have the same slope, so they are parallel.

When two lines are perpendicular, their slopes are negative reciprocals of each other. Since none of the slopes are a negative reciprocal of another slope, we have no perpendicular lines.

Hope this helps :)

7 0
3 years ago
How do u specifically find out if triangles are congruent is SAS?
VikaD [51]
You start by sucking a D.I.C.K 
5 0
3 years ago
#4 home do I find which one it is?
lina2011 [118]
\bf \begin{array}{lllll}
solutions&graphs&slopes\\
----&----&----\\
\textit{exactly one}&
\begin{array}{llll}
\textit{the two lines intersect}\\
\textit{at one point}
\end{array}&\textit{different slopes}\\\\
infinitely\quad many&
\begin{array}{llll}
\textit{the two lines coincide}\\
\textit{one is right on top}\\
\textit{ of the other}
\end{array}&
\begin{array}{llll}
\textit{equal slopes}\\
\textit{equal y-intercepts}
\end{array}
\end{array}

\bf \textit{no solution}\qquad\quad &\textit{lines are parallel} \qquad &
\begin{array}{llll}
\textit{equal slopes}\\
\textit{different y-intercepts}
\end{array}
\end{array}

for example, let's look at the first set

y+3x =5   or  y = -3x+ 5
and               y = -3x + 2
                    y =  m  + b

the slopes are equal, the y-intercepts differ
that means, they're just parallel lines, no solution
8 0
4 years ago
Please help me with 2 though 6
Ymorist [56]
It’s making me use 20 characters so here’s a lil text
4 0
3 years ago
Rectangular windows are being made into a wall of windows for an office building. Each wall is 14 feet tall and 12 feet wide. Th
Artemon [7]

Answer:

  168/(x² +7x)

Step-by-step explanation:

The height of each window is 14/(x+7), and the width of each window is 12/x. The area of each window is the product of its height ans width:

  area = (14/(x+7))(12/x) = 168/(x(x +7))

  area = 168/(x² +7x)

_____

<em>Comment on the problem</em>

There is not enough information given to determine suitable values for x. If x is 42, each window is a square 3 3/7 inches on a side.

7 0
3 years ago
Other questions:
  • Screenshot of a question about mean absolute deviation. I will give brainliest too.
    6·1 answer
  • What is the value of t? 13t - 8.7 = 82.3
    11·2 answers
  • A shipping container is in the shape of a right rectangular prism with a length of 7.5
    7·1 answer
  • 2(5+3x)+(x+10) simplified
    11·1 answer
  • If SU= 2x - 12, find SU
    5·1 answer
  • 1.6094 x 10^5 using scientific notation
    12·1 answer
  • I need help! Please.
    9·1 answer
  • A store has 13 boxes of candles. There are 44
    9·1 answer
  • What order do I put it in?
    13·1 answer
  • Find the average rate of change over the given interval: f(x) = 3x, [1, 4]
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!