Answer:11.59 J
Explanation:
Given
mass of Particle 
Initially Particle moves towards left 
Final velocity of Particle is towards Right 
According to Work Energy theorem
Work done by all the Forces=change in Kinetic Energy
Work done by Force
![W=\frac{69\times 10^{-3}}{2}\left [ 31^-25^2\right ]](https://tex.z-dn.net/?f=W%3D%5Cfrac%7B69%5Ctimes%2010%5E%7B-3%7D%7D%7B2%7D%5Cleft%20%5B%2031%5E-25%5E2%5Cright%20%5D)
![W=\frac{69\times 10^{-3}}{2}\left [ 961-625\right ]](https://tex.z-dn.net/?f=W%3D%5Cfrac%7B69%5Ctimes%2010%5E%7B-3%7D%7D%7B2%7D%5Cleft%20%5B%20961-625%5Cright%20%5D)
<span>Boyle's Law, because it describes what will happen in the relationship between the pressure and volume of the gas.</span>
Answer:
1 KM per minute is the real speed in minutes, turn that into 1000 meters per minute and divided by 60, you get a good number of 16.6666666667 which means you could go 50 meters per 3 seconds
Explanation:
so it would be 16.6666666667 meters per second
Answer:
the magnitude of the velocity of the block just after impact is 2.598 m/s and the original speed of the bullect is 324.76m/s.
Explanation:
a) Kinetic energy of block = potential energy in spring
½ mv² = ½ kx²
Here m stands for combined mass (block + bullet),
which is just 1 kg. Spring constant k is unknown, but you can find it from given data:
k = 0.75 N / 0.25 cm
= 3 N/cm, or 300 N/m.
From the energy equation above, solve for v,
v = v √(k/m)
= 0.15 √(300/1)
= 2.598 m/s.
b) Momentum before impact = momentum after impact.
Since m = 1 kg,
v = 2.598 m/s,
p = 2.598 kg m/s.
This is the same momentum carried by bullet as it strikes the block. Therefore, if u is bullet speed,
u = 2.598 kg m/s / 8 × 10⁻³ kg
= 324.76 m/s.
Hence, the magnitude of the velocity of the block just after impact is 2.598 m/s and the original speed of the bullect is 324.76m/s.
D. Power. The unit of power is watt.
