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nignag [31]
3 years ago
14

A certain AM radio wave has a frequency of

Physics
1 answer:
Andreas93 [3]3 years ago
3 0

Answer:

267 m

Explanation:

v=λf

v= 2.99*10^8m/s

λ=?

f=1.12*10^6Hz

2.99*10^8=(1.12*10^6)λ

λ=267 m

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A 69 g particle is moving to the left at 25 m/s . How much net work must be done on the particle to cause it to move to the righ
LekaFEV [45]

Answer:11.59 J

Explanation:

Given

mass of Particle m=69 gm

Initially Particle moves towards left v_1=25 m/s

Final velocity of Particle is towards Right v_2=31 m/s

According to Work Energy theorem

Work done by all the Forces=change in Kinetic Energy

Work done by Force=\frac{mv_2^2}{2}-\frac{mv_1^2}{2}

W=\frac{69\times 10^{-3}}{2}\left [ 31^-25^2\right ]

W=\frac{69\times 10^{-3}}{2}\left [ 961-625\right ]

W=11.59 J

5 0
4 years ago
A teacher explains that a scientist named Boyle did many experiments to determine what the relationship is between the volume an
lina2011 [118]
<span>Boyle's Law, because it describes what will happen in the relationship between the pressure and volume of the gas.</span>
4 0
4 years ago
Convert 60 km/ hr into m/s
elixir [45]

Answer:

1 KM per minute is the real speed in minutes, turn that into 1000 meters per minute and divided by 60, you get a good number of 16.6666666667 which means you could go 50 meters per 3 seconds

Explanation:

so it would be 16.6666666667 meters per second

4 0
3 years ago
A rifle bullet with mass ma = 8.00 g strikes and embeds itself in a block with mass mb = 0.992 kg that rests on a frictionless,
Doss [256]

Answer:

the magnitude of the velocity of the block just after impact is 2.598 m/s and the original speed of the bullect is 324.76m/s.

Explanation:

a)  Kinetic energy of block = potential energy in spring  

½ mv² = ½ kx²

Here m stands for combined mass (block + bullet),

which is just 1 kg.  Spring constant k is unknown, but you can find it from given data:  

k = 0.75 N / 0.25 cm

= 3 N/cm, or 300 N/m.  

From the energy equation above, solve for v,

v = v √(k/m)  

= 0.15 √(300/1)

= 2.598 m/s.

b)  Momentum before impact = momentum after impact.

Since m = 1 kg,

v = 2.598 m/s,

p = 2.598 kg m/s.  

This is the same momentum carried by bullet as it strikes the block.  Therefore, if u is bullet speed,  

u = 2.598 kg m/s / 8 × 10⁻³ kg

= 324.76 m/s.

Hence, the magnitude of the velocity of the block just after impact is 2.598 m/s and the original speed of the bullect is 324.76m/s.

6 0
3 years ago
The rate at which work is done is called ____.
alekssr [168]
D. Power. The unit of power is watt.
6 0
3 years ago
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