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frez [133]
3 years ago
13

What volume in liters of chlorine gas would be fully required to react to 125 g of Nal

Chemistry
1 answer:
Ivahew [28]3 years ago
4 0

Volume of Cl₂ = 9.34 L

<h3>Further explanation</h3>

Reaction

2NaI + Cl₂ ⇒ 2NaCl + I₂

mol NaI (MW=149,89 g/mol) :

\tt \dfrac{125}{149,89}=0.834

mol Cl₂ : mol NaI = 1 : 2

mol Cl₂ :

\tt \dfrac{1}{2}\times 0.834=0.417

Assumptions at STP(1 mol=22.4 L) :

\tt 0.417\times 22.4~L=9.34~L

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