Answer:
A molecular formula consists of the chemical symbols for the constituent elements followed by numeric subscripts describing the number of atoms of each element present in the molecule.
The molecular formula of the given compounds are:
- CaSO4
- Na₂CO₃
- H2O
- CO2
- KNO3
- NH4Cl
Answer : The percent of aluminium in
is 
Solution :
Molar mass of Aluminium = 26.98 g/mole
Molar mass of
= 342.15 g/mole
First we have to calculate the mass of Aluminium.
Mass of 2 Al atoms = 2 × 26.98 g/mole = 53.96 g/mole
Now we have to calculate the percent composition of Aluminium in 

Now put all the given values in this formula, we get


Therefore, the percent of aluminium in
is 
The individual numbers which are present in chemical formula is subscript.
<h3>What is chemical formula?</h3>
Chemical formula of any compound of chemistry consist more than one atoms in it and gives idea about the number of atoms present in that compound.
Given chemical formula of glucose is C₆H₁₂O₆.
In the given chemical formula of glucose, number which shows the amount of carbon, hydrogen and oxygen are known as subscripts.
Hence, individual number are subscript.
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the pH during the titration of 40.00 mL of 0.1000 M HCl after adding 50 mL of 0.1000 M NaOH is pH = 13.39
NaOH + HCl → NaCl + H2O
40.00 ml 0.5M NaOH solution
mol NaOH = 40 ml / 1000 ml / L * 0.5 mol / L = 0.02 mol NaOH
25 mL 0.1 M HCl
mol HCl = 25 mL / 1000 mL / L * 0.1 mol / L = 0, 0025 mol
This reacts with 0.0025 mol NaOH
[NaOH] = 0.269 M
[OH-] = 0.269 M
pOH = - log 0.269
pOH = 13.43
You titrate with 30 mL 0.100 M HCl
Mol HCl = 30 mL / 1000 mL/L * 0.100 mol /L = 0.003 mol HCl
This will react with 0.003 mol NaOH
Mol unreacted NaOH = 0.02 mol - 0.003 mol = 0.017 mol NaOH in 40mL + 30 mL = 70 mL solution
Molarity of NaOH solution = 0.017 mol / 70 mL * 1000 mL/L = 0.243 M
[OH-] = 0.243 M
pOH = - log 0.243
pOH = 0.61
pH = 13.39
40 mL
Titration is defined as "the process of determining the amount of substance A by adding a measured amount of substance B, which is a titrator that reacts until an accurate chemical equivalence point is reached."
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