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zzz [600]
3 years ago
14

Hey guys please help me on this I will give you brainliest

Mathematics
1 answer:
dangina [55]3 years ago
6 0

Answer:

1. 15-5x 2. 54+18x 3. 3x+15 4. 28x+56

Step-by-step explanation:

I dont get  if you need this or the real answer if you need the real answer let me know and I will give you the real answer. :) Have a good day!

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Need help thanks I’ll give brainiest or whatever it’s called
ANTONII [103]

Answer:

∠1 = 144°

∠2 = 144°

∠3 = 36°

∠4 = 90°

∠5 = 144°

∠6 = 36°

∠7 = 144°

∠8 = 90°

6 0
3 years ago
Read 2 more answers
WILL MARK BRAINLIEST AND WORTH 30 POINTS
BabaBlast [244]

Answer:

The growth factor of <em>f(x)</em> is <em>less</em><em> </em><em>than</em><em> </em>the growth factor of <em>g(x)</em>.

Explanation:

\displaystyle g(x) = 3(4)^x \\ \\ f(x) = 4(3)^x

<em>x</em><em> </em> | <em>f(x)</em>

_____

0 | 4

1 | 12

2 | 36

You can tell because the <em>g</em><em>(</em><em>x</em><em>)</em><em> </em>function is multiplying by 4, while the <em>f</em><em>(</em><em>x</em><em>)</em><em> </em>function is multiplying by 3.

I am joyous to assist you anytime.

5 0
3 years ago
Help ill give brainiest &lt;3 dont guess
Marizza181 [45]

Answer:

rectangular prism, 6 faces, 8 vertices

5 0
3 years ago
Read 2 more answers
You believe the population is normally distributed. Find the 80% confidence interval. Enter your answer as an open-interval (i.e
victus00 [196]

You intend to estimate a population mean μ from the following sample. 26.2 27.7 8.6 3.8 11.6 You believe the population is normally distributed. Find the 80% confidence interval.  Enter your answer as an open-interval (i.e., parentheses) accurate to twp decimal places.

Answer:

The  Confidence interval = (8.98 , 22.18)

Step-by-step explanation:

From the given information:

mean = \dfrac{ 26.2+ 27.7+ 8.6+ 3.8 +11.6 }{5}

mean = 15.58

the standard deviation \sigma = \sqrt{\dfrac{\sum(x_i - \mu)^2 }{n}}

the standard deviation = \sqrt{\dfrac{(26.2  - 15.58)^2 +(27.7 - 15.58)^2 +(8.6  - 15.58)^2 + (3.8  - 15.58)^2  + (11.6  - 15.58)^2  }{5 }  }

standard deviation = 9.62297

Degrees of freedom df = n-1

Degrees of freedom df = 5 - 1

Degrees of freedom df = 4

For df  at 4 and 80% confidence level, the critical value t from t table  = 1.533

The Margin of Error M.O.E = t \times \dfrac{\sigma}{\sqrt{n}}

The Margin of Error M.O.E = 1.533 \times \dfrac{9.62297}{\sqrt{5}}

The Margin of Error M.O.E = 1.533 \times 4.3035

The Margin of Error M.O.E = 6.60

The  Confidence interval = ( \mu  \pm M.O.E )

The  Confidence interval = ( \mu  +  M.O.E , \mu - M.O.E )

The  Confidence interval = ( 15.58 - 6.60 , 15.58 + 6.60)

The  Confidence interval = (8.98 , 22.18)

7 0
3 years ago
Quadrilateral ABCD is translated to get quadrilateral A′B′C′D′. Vertex A is at (-5, 2), and vertex A′ is at (2, -2).
fgiga [73]
Then vertex B’ is at (1,1)
proof: the translation from A to A’ is (7,-4) therefore applying the same conditions to B would give you the outcome of (1,1)
4 0
2 years ago
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