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3 years ago

Help me please will give brainliest

Mathematics

1 answer:

lawyer [7]3 years ago

7 0

Answer:

chupas trozon

Step-by-step explanation:

pastilla te entra mi trozon

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NEED HELP I GOT 15MINS%$!

goldenfox [79]

Answer:

The answer is option 2.

Step-by-step explanation:

First, you have to eliminate brackets, you have to divide -1.5 to both sides :

$- 1.5(4 - r) = - 12$

$- 1.5(4 - r) \div - 1.5= - 12 \div - 1.5$

$4 - r = 8$

Next you have to solve r :

$4 - r = 8$

$- r = 8 - 4$

$- r = 4$

$r = - 4$

8 0

4 years ago

Read 2 more answers

Solve the equation. <br> ×-9=-6× + 5

Serggg [28]

The answer is x=2. You add 6x to both sides to get 7x-9=5 then add 9 to both sides to get 7x=14. From there, you divide by 7 on both sides to get x=2.

6 0

4 years ago

Read 2 more answers

How many integers $m$ are there such that $0

Alexandra [31]

Answer:

I think you meant to put an attachment but I don't see one

Step-by-step explanation:

3 0

3 years ago

A common inhabitant of human intestines is the bacterium Escherichia coli. A cell of this bacterium in a nutrient-broth medium d

qwelly [4]

Answer:

Step-by-step explanation:

Given that,

Cells are divided into two cell every 20mins, this implies that the half-life is 20mins

Initial population growth is 60cells

Growth rate r?

Population growth is modeled as

P(t) = Po•exp(rt)

Where,

Po is the initial growth at t= 0

Po= 60

P(t) is population at any time t.

Since the population doubles every 20mins(⅓hr)

Then, P(⅓) = 2×60 =120

Then, P(t) = 120cells

So, applying the formula

P(t) = Po•exp(rt)

120 = 60•exp(⅓r)

120/60 = exp(r/3)

2 = exp(r/3)

Take In of both sides

In(2) = r/3

Cross multiply

r = 3In(2)

r = 2.079 /hour

The growth rate is 2.079/hour.

7 0

3 years ago

A cup of coffee contains about 100 mg of caffeine. Caffeine is metabolized and leaves the body at a continuous rate of about 12%

Mamont248 [21]

Answer:

a. $A = C_{0}(1-x)^t\\x: percentage\ of \ caffeine\ metabolized\\$

b. $\frac{dA}{dt}= -11.25 \frac{mg}{h}$

Step-by-step explanation:

First, we need tot find a general expression for the amount of caffeine remaining in the body after certain time. As the problem states that every hour x percent of caffeine leaves the body, we must substract that percentage from the initial quantity of caffeine, by each hour passing. That expression would be:

$A= C_{0}(1-x)^t\\t: time \ in \ hours\\x: percentage \ of \ caffeine\ metabolized\\$

Then, to find the amount of caffeine metabolized per hour, we need to differentiate the previous equation. Following the differentiation rules we get:

$\frac{dA}{dt} =C_{0}(1-x)^t \ln (1-x)\\\frac{dA}{dt} =100*0.88\ln(0.88)\\\frac{dA}{dt} =-11.25 \frac{mg}{h}$

The rate is negative as it represents the amount of caffeine leaving the body at certain time.

3 0

3 years ago

Help me please will give brainliest​

Help me please will give brainliest