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yulyashka [42]
3 years ago
5

What is the conjugate acid in the following equation:

Chemistry
1 answer:
yanalaym [24]3 years ago
5 0

Answer:

HNO₂

Explanation:

An acid is a proton donor; a base is a proton acceptor.

Thus, NO₂⁻ is the base, because it accepts a proton from the water.

H₂O is the acid, because it donates a proton to the nitrite ion.

The conjugate base is what's left after the acid has given up its proton.

The conjugate acid is what's formed when the base has accepted a proton.

NO₂⁻/HNO₂ make one conjugate acid/base pair, and H₂O/OH⁻ are the other conjugate acid/base pair.

NO₂⁻ + H₂O ⇌ HNO₂ + OH⁻

base     acid     conj.      conj.

                        acid       base

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Vanyuwa [196]

Answer:

national flower : Rhododendron

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4 0
3 years ago
What element is being oxidized in the following redox reaction?
GrogVix [38]

Answer:

The O is being oxidized, but at the same time, is being reducted.

Explanation:

H₂O₂(l) + ClO₂(aq) → ClO₂(aq) + O₂(g)

In this reaction, we have 4 compounds:

Hydrogen peroxide

Chlorine dioxide (twice)

Oxygen

In both dioxide, the Cl acts with +4 in oxidation state; the oxygen acts with -2.

Oxgen in ground state has 0, as oxidation number.

In peroxide, the H acts with +1 but  the oxygen acts with -1.

Peroxide is making the oxidation number from the O in the ClO₂, to decrease (reduction) and to increase in the O, at the ground state.

Hydrogen peroxide is a good reducing and oxidizing agent at the same time.

4 0
3 years ago
How many atoms are in 0.3500 mol of gold
Vikentia [17]
8798076 atoms are in a 0.3500 mol of gold

3 0
3 years ago
Note: Please show all work and calculation setups to get full credit. T. he following may be used on this assignment: specific h
olga55 [171]

Answer:

16974J of energy are required

Explanation:

The energy required is:

* The energy to heat solid water from -15°C to 0°C using:

q = m*S*ΔT

* The energy to convert the solid water to liquid water:

q = dH*m

* The energy required to increase the temperature of liquid water from 0°C to 75°C

q = m*S*ΔT

The first energy is:

q = m*S*ΔT

<em>m = Mass water = 25g</em>

<em>S is specific heat of ice = 2.03J/g°C</em>

<em>ΔT is change in temperature = 0°C - (-15°C) = 15°C</em>

q = 25g*2.03J/g°C*15°C

q = 761.3J

The second energy is:

q = dH*m

<em>m = Mass water = 25g</em>

<em>dH is heat of fusion of water = 80cal/g</em>

q = 80cal/g*25g

q = 2000cal * (4.184J/1cal) = 8368J

The third energy is:

q = m*S*ΔT

<em>m = Mass water = 25g</em>

<em>S is specific heat of water= 4.184J/g°C</em>

<em>ΔT is change in temperature = 75°C-0°C = 75°C</em>

q = 25g*4.184J/g°C*75°C

q = 7845J

The energy is: 7845J + 8368J + 761J =

16974J of energy are required

3 0
2 years ago
Chlorine gas is added to a large flask to a pressure of 1.85 atm, at a temperature of 322 K. Phosphorus is added, and a reaction
AVprozaik [17]

Answer:

The volume of the flask is<u> 20.245 litres .</u>

Explanation:

We are given with following information-

PV=nRT -------- 1

where R =0.0821L.atom/mole.K

Molar mass of PCl_5=208.22g/mole

The given chemical equation is -

2P _(_s_)+5Cl_2 _(_g_)\rightarrow2PCl_5  _(_s_) --------- 2

Now , calculation -

Mass of PCl_5 formed = 118g

Molar mass of PCl_5 = 208.22g/mole

      Mole = \frac{mass (g)}{molar mass}

Therefore , moles of PCl_5 formed = \frac{118}{208.22}

     From equation 2 , we get to know that ,

 2mole PCl_5 formed from 5 mole Cl_2 _(_g_)

Therefore , \frac{118}{208.22} mole PCl_5 formed from \frac{5}{2} \times\frac{118}{208.22} mole Cl_2 _(_g_)

Moles of Cl_2 _(_g_) used =\frac{5\times118}{2\times208.22} mole

R= 0.0821L.atom/mole.K

Pressure (P)= 1.85atm

Temperature (T)= 322K

Moles of  Cl_2 _(_g_) (n)= \frac{5}{2} \times\frac{118}{208.22} moles

Applying  the formula above in 1 equation , that is

PV = nRT

putting the given values -

1.85 \times V=\frac{5}{2} \times\frac{118}{208.22}\times0.0821\times322

 V = 20.245 litres.

Hence , the volume of the flask is <u>20.245 litres . </u>

 

8 0
3 years ago
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