Please help me. Clear answer please and the formula and everything
1 answer:
(a) At level A Potential Energy is 2940 J.
(b) At level B Potential Energy is 1960 J.
(c) At level C Potential energy is 1470 J.
(d) At level D Potential energy is 0 J.
(e) The change in Potential energy if the object moves from A to B is 980 J.
<u>Explanation</u>:
Given that,
Mass of an object is 5 kg (m) at a height of 60 m (h) above the ground as shown in the given figure.
Potential energy of an object is calculated by using the formula m × g × h. “g” is acceleration due to gravity on earth is 9.8 .
(a) At level A:
At height (h) is 60 m above ground.
Potential energy = 5 × 9.8 × 60
Potential energy = 2940 J
(b) At level B:
At height (h) is 40 m above ground.
Potential energy = 5 × 9.8 × 40
Potential energy = 1960 J
(c) At level C:
At height (h) is 30 m above ground.
Potential energy = 5 × 9.8 × 30
Potential energy = 1470 J
(d) At level D:
At height (h) is 0 m above ground (object is on the ground).
Potential energy = 5 × 9.8 × 0
Potential energy = 0 J
(e) Change in “Potential energy” when it moves from “A” to “B”
Change in “Potential energy” in difference in initial “Potential energy” (at level A) and final “Potential energy” (at level B)
= 2940 - 1960
= 980 J
Therefore, change in “Potential energy” is 980 J.
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Answer:
Twice as fast
Explanation:
Solution:-
- The mass of less massive cart = m
- The mass of Massive cart = 2m
- The velocity of less massive cart = u
- The velocity of massive cart = v
- We will consider the system of two carts to be isolated and there is no external applied force on the system. This conditions validates the conservation of linear momentum to be applied on the isolated system.
- Each cart with its respective velocity are directed at each other. And meet up with head on collision and comes to rest immediately after the collision.
- The conservation of linear momentum states that the momentum of the system before ( P_i ) and after the collision ( P_f ) remains the same.
- Since the carts comes to a stop after collision then the linear momentum after the collision ( P_f = 0 ). Therefore, we have:
- The linear momentum of a particle ( cart ) is the product of its mass and velocity as follows:
m*u - 2*m*v = 0
Where,
( u ) and ( v ) are opposing velocity vectors in 1-dimension.
- Evaluate the velcoity ( u ) of the less massive cart in terms of the speed ( v ) of more massive cart as follows:
m*u = 2*m*v
u = 2*v
Answer: The velocity of less massive cart must be twice the speed of more massive cart for the system conditions to hold true i.e ( they both come to a stop after collision ).
Answer:
The total momentum after the collision is 1 kg-m/s.
Explanation:
We have,
Mass of a steel sphere is 0.5 kg
It is travelling with a speed of 2 m/s
It collides with an identical sphere at rest.
The law of conservation of momentum states that the initial momentum is equal to the final momentum for an isolated system. Here, initial momentum is :
So, the total momentum after the collision is 1 kg-m/s.