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Vladimir [108]
4 years ago
15

A company surveyed 1000 people on their age and the number of jeans purchased annually. The results of the poll are shown in the

table. Jeans Purchased Annually 0 1 2 3 or More Total Under 12 0 69 78 73 220 12-18 10 75 70 65 220 19-25 40 77 97 76 290 over 25 36 86 128 20 270 Total 86 307 373 234 1000 A person is selected at random. Compute the probability of the following. (a) The person is over 25 and purchases 3 or more pairs of jeans annually. 0.2 Incorrect: Your answer is incorrect. (b) The person is older than 18 or purchases 1 pair of jeans annually. 0.163 Incorrect: Your answer is incorrect. (c) The person is in the age group 12-18 and purchases at most 2 pairs of jeans annually. 0.07 Incorrect: Your answer is incorrect.
Mathematics
1 answer:
PIT_PIT [208]4 years ago
8 0

Answer:

a) 0.02; b) 0.704; c) 0.155

Step-by-step explanation:

a) In the row of people over 25, there are 20 in the column for 3 or more; this is out of 1000 people.  This makes the probability 20/1000 = 0.02.

b) There are two rows that are greater than 18 in age, 19-25 and over 25.  This is a total of 290+270 = 560 in these two rows.  There are also 307 people that purchased only one pair of jeans; this makes a total of 560+307 = 867 people.  However, some of these are counted twice; there are 77 people in the 19-25 category that only purchased one pair and 86 people in the over 25 category that only purchased one pair.  Taking these doubles out, we have

867-(86+77) = 704 people out of 1000; this is 704/1000 = 0.704.

c) In the 12-18 category, 10 people purchased 0 pairs, 75 people purchased 1 pair and 70 people purchased 2 pairs; this is 10+75+70 = 155 people.  This is out of 1000 people; this gives us 155/1000 = 0.155.

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Step-by-step explanation:

The random variable <em>X </em>is defined as the number of correct answers given by a person who is guessing each answer on a 25-question exam.

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This implies that the probability of getting a correct answer is:

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There are a total of <em>n</em> = 25 questions.

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(a)

The random variable <em>X</em> has  finite number of independent trials (i.e. 25 questions). There are only two outcomes for each trial, i.e. Success = correct answer and Failure = wrong answer. Each trial has the same probability of success (, i.e. P (X) = 0.25).

Thus, the probability distribution of the random variable <em>X</em> is Binomial with parameters <em>n</em> = 25 and <em>p</em> = 0.20.

(b)

Compute the mean of the random variable <em>X</em> as follows:

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Compute the standard deviation of the random variable <em>X</em> as follows:

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(c)

The sample is large and the probability of success is close to 0.50.

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1. np ≥ 5

2. n(1 - p) ≥ 5

Check the conditions as follows:

np=25\times 0.20=5=5\\\\n(1-p)=25\times (1-0.20)=20>5

Thus, a Normal approximation to binomial can be applied.

So,  X\sim N(5, 2^{2})

It is provided that the minimum passing score foe the test is such that only 1% of students who are guessing will pass the test.

That is P (X < x) = 0.01.

⇒ P (Z < z) = 0.01

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z=\frac{x-\mu}{\sigma}\\\\-2.33=\frac{x-5}{2}\\\\x=5-(2.33\times 2)\\\\x=0.34

Thus, the value of <em>x</em> is 0.34.

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