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zhannawk [14.2K]
3 years ago
9

I don't understand how to do this, 6x + 6/6 > 1/3x + 2

Mathematics
1 answer:
-BARSIC- [3]3 years ago
5 0

Answer:

X> 3/17

Step-by-step explanation:

6x+ 6/6 > 1/3x + 2

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Which ratio would help find the distance the person is from the flag pole ¨X¨ if the angle is elevation of 30 degrees.
WINSTONCH [101]

Answer:

There are three major trignometric ratios in mathematics and they are:

sine(sin), cosine(cos) and tangent(tan). A popular acronym is used in recalling the formula for each ratio and it is: SOH-CAH-TOA.

Sine(x) = Opp/Hyp

Cosine(x) = Adj/Hyp

Tangent(x) = Opp/Adj

Now, the Hyp is the hypothenus of the triangle and it is the side opposite to angle 90. The opposite and adjacent is kind of relative depending on the angle been considered. For this case, we are considering angle 30 which the opposite side is 60 and the remaining side becomes the adjacent

Step-by-step explanation:

tan 30 = 60/x

5 0
3 years ago
PLEASE HELP NEED THIS ANSWERED CORRECTLY
Helen [10]

f(3) = 1.9

Solution:

Given function:

$f(x)=\frac{14}{7+2 e^{-0.6 x}}

To find f(3):

Substitute x = 3 in the given function.

$f(3)=\frac{14}{7+2 e^{-0.6 (3)}}

$f(3)=\frac{14}{7+2 e^{-1.8}}

Let us first simplify 2e^{-1.8}.

Apply exponent rule: a^{-b}=\frac{1}{a^{b}}

$ 2e^{-1.8}=2\frac{1}{e^{1.8}}$

The value of e^{1.8}=6.04964. (using calculator)

$\frac{2}{e^{1.8}}=\frac{2}{6.04964}=0.33059

2e^{-1.8}=0.33059

Substitute this value in f(3).

$f(3)=\frac{14}{7+0.33059}

$f(3)=\frac{14}{7.33059}  

$f(3)=1.90980

f(3) = 1.9

Hence the value of f(3) is 1.9.

3 0
3 years ago
What is the product of 1/2 times 2/3 times 3/4 .... times 1999/2000?
Phantasy [73]
1/2 * 2/3 *3/4 * ... * 1999/2000
Observe, every numerator cancels with denominator
that leaves 1/2000
3 0
3 years ago
Find the distance between (-2, 8) and (11, 2). Round to the nearest hundredth.
MakcuM [25]

Answer:

14.32

Step-by-step explanation:

We can find the distance using the distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We then substitute (-2,8) as (x_1,y_1) and (11,2) as (x_2,y_2).

d=\sqrt{(11--2)^2+(2-8)^2} \\d=\sqrt{(13)^2+(-6)^2} \\d=\sqrt{169+36}\\d=\sqrt{205}=14.32

6 0
3 years ago
Check all the true statements.
andrew-mc [135]

Answer:

The true statements are:

  • 2DE = AC
  • 1/2AC = DE
  • DE || AC  

Step-by-step explanation:

As we are given,

AD = 3.5 and BD = 3.5

CE = 3 and BE = 3

From the given triangle ΔABC, it is clear that:

The segment DE bisects the sides AB and BC, so

AD = BD

CE = BE

It is clear that the segment DE is parallel to the segment AC, thus

DE || AC  

As DE is the midsegment between AB and BC, so

2DE = AC

1/2AC = DE

Thus, the true statements are:

  • 2DE = AC
  • 1/2AC = DE
  • DE || AC  
5 0
2 years ago
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