Hi there!
We are told to write an equation of a line in standard form with a slope for 3 that goes through the point (9,-4). There are many ways to do this, but the easiest one would be using the point-slope form. This is the point-slope form:
If we let m = 3, y1 = -4, x1 = 9, we can substitute the values back into the equation to get:
. We can simplify the equation to get
. Now, we combine like terms by subtracting 4 from both sides, giving us y = 3x - 31. Finally, we subtract 3x from both sides to get -3x + y = -31. Therefore, the answer to your query is
-3x + y = -31.
The numbers do not seem to work out, lol.
A rhombus has diagonals intersect at right-angles. All four sides of a rhombus are equal. So we end up with four right-angled triangle with a hypotenuse of 34, and one leg equal to the half (long) diagonal of 13.
This makes the other leg about 31 long, or a diagonal of 62, longer than the "long diagonal" of 26.
I suspect the question should read the longer semi-diagonal is 26.
Based on that, the other leg is sqrt(34^2-26^2)=21.91.
The greater half-angle therefore has a tangent of 26/21.91=1.1867, and the corresponding half-angle is 49.88 degrees.
The larger angle of the rhombus is therefore 2*49.88=99.76 degrees.
Answer: A. mark as brainliest
Step-by-step explanation: dont need to