9 watches should be served.
Area of rectangle is 168
Step-by-step explanation:
Given,
Base = 14mm
Perimeter = 52mm
We will find length first to calculate area of rectangle.
Let l be the length of rectangle.
As we know,
Perimeter = 2(length + base)
52=2(l+14)
Now,
Area of rectangle= Length * Base
Area of rectangle is 168
Keywords: Area, Rectangles
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To find fractions that are equivalent to 4/7, just multiply the numerator and denominator by a number.
4/7 X 2/2 = 8/14.
4/7 X 3/3 = 12/21.
4/7 X 4/4 = 16/28.
4/7 X 5/5 = 20/35.
4/7 X 6/6 = 24/42.
4/7 X 7/7 = 28/49.
4/7 X 8/8 = 32/56.
4/7 X 9/9 = 36/63.
4/7 X 10/10 = 40/70.
The bolded fractions are equivalent to 4/7.
Answer:
5/15
Step-by-step explanation:
Out of 15, 5 are yellow. Converted to a fraction this will be 5/15. Hope this helps!! :)
Answer:
For each boy , we know that there is a girl who solved a question in with him. Since a boy solve at most six questions, for a boy and his set of such questions there are at least 11 girls who solve a question in common with the boy such that at least three boys solve that common question. The girls have solved a total of at most 21×6 questions, this can be view as a set with repeated element i.e if a question is solved by more than one girl it appears as many times as the number of girls who have solved it. Let these set of questions be noted as A. Clearly, set A has a size 21×6. We mark each question in set A which has been solved by at least three girls and a boy and we mark it the number of times that is the same as the number of boys that have solved it. Since there are total of 21×11 marks (since there are at least 11 marks for each boy, either a question is marked at least three times, in which case we are done since it has been solved by at least three girls and three boys. Or each question has been marked at most twice. In this case it is clear that more than 21×5 questions in set A have been marked since 26×5×4<21×11 (there are total of 21×11 marks). This implies that there is a girl such that all six of her questions have been marked. By then there must be a question that this girl has solved which has also been solved by at least three boys. Therefore, it must be true that there is a question such that it has been solved by at least three people of each gender.