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Free_Kalibri [48]
3 years ago
10

How many oxygen atoms are in 1.00 g of quartz?

Chemistry
1 answer:
Arturiano [62]3 years ago
4 0
<span>2.00 x 10^22 atoms The empirical formula for quartz is SiO2, so calculate the molar mass of quartz. Silicon = 28.0855 Oxygen = 15.999 Molar mass = 28.0855 + 2 * 15.999 = 60.0835 Now divide the mass you have of quartz by its molar mass 1.00 g / 60.0835 g/mol = 0.016644 mol Since you have 2 moles of oxygen atoms per mole of quartz, multiply by 2 0.016644 mol * 2 = 0.033288 mol Finally, multiply by avogadro's number to get the number of atoms. 0.033288 mol * 6.0221409e+23 atoms/mol = 2.00465 x 10^22 Round to 3 significant figures to get 2.00 x 10^22</span>
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f an electron has a mass of 9.709 x 10-31 kg, and a proton has a mass of 1.672 x 10-27 kg, approximately how many electrons are
VikaD [51]

Answer:

The answer is 1722 e⁻

Explanation:

Let's make a rule of three:

9.708×10⁻³¹ kg is the mass of 1 e⁻

1.672 ×10⁻²⁷ kg (which is 1 p⁺), how many e⁻ does it contain.?

1.672 ×10⁻²⁷ kg / 9.708×10⁻³¹ kg

The answer is 1722 e⁻

3 0
3 years ago
Sound waves are mechanical waves in which the particles in the medium vibrate in a direction parallel to the direction of energy
Marat540 [252]
Longitudinal wave is the another name.
3 0
4 years ago
A buffer solution contains 0.496 M hydrocyanic acid and 0.399 M sodium cyanide . If 0.0461 moles of sodium hydroxide are added t
pochemuha

Answer : The pH of the solution is, 9.63

Explanation : Given,

The dissociation constant for HCN = pK_a=9.31

First we have to calculate the moles of HCN and NaCN.

\text{Moles of HCN}=\text{Concentration of HCN}\times \text{Volume of solution}=0.496M\times 0.225L=0.1116mole

and,

\text{Moles of NaCN}=\text{Concentration of NaCN}\times \text{Volume of solution}=0.399M\times 0.225L=0.08978mole

The balanced chemical reaction is:

                          HCN+NaOH\rightarrow NaCN+H_2O

Initial moles     0.1116       0.0461     0.08978

At eqm.       (0.1116-0.0461)    0       (0.08978+0.0461)

                        0.0655                       0.1359

Now we have to calculate the pH of the solution.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

Now put all the given values in this expression, we get:

pH=9.31+\log (\frac{0.1359}{0.0655})

pH=9.63

Therefore, the pH of the solution is, 9.63

4 0
3 years ago
Which is a true statement about an exterior angle of a triangle?
wolverine [178]

The only true statement about an exterior angle of a triangle from the above is that it forms a linear pair with one of the interior angles of the triangle.

<h3>What is a triangle?</h3>

A triangle can be defined as a one of the plane shapes which has three sides and three angles

So therefore, the only true statement about an exterior angle of a triangle from the above is that it forms a linear pair with one of the interior angles of the triangle.

Learn more about triangles:

brainly.com/question/2217700

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7 0
2 years ago
Suppose you start with a solution of red dye #40 that is 2.3 ✕ 10−5 M. If you do three successive volumetric dilutions pipetting
larisa [96]

Answer: Therefore, the concentration of final solution is 4.0\times 10^{-8}M

Explanation:

According to the neutralization law,

M_1V_1=M_2V_2

where,

M_1 = molarity of stock solution = 2.3\times 10^{-5}M

V_1 = volume of stock solution = 3.00 ml

M_2 = molarity of diluted solution = ?

V_2 = volume of diluted solution = 25.00 ml

2.3\times 10^{-5}M\times 3.00=M_2\times 25.00

M_2=0.28\times 10^{-5}M

Therefore, the concentration of diluted solution is 0.28\times 10^{-5}M

2) On further dilution

M_1V_1=M_2V_2

where,

M_1 = molarity of stock solution = 0.28\times 10^{-5}M

V_1 = volume of stock solution = 3.00 ml

M_2 = molarity of diluted solution = ?

V_2 = volume of diluted solution = 25.00 ml

0.28\times 10^{-5}M\times 3.00=M_2\times 25.00

M_2=0.034\times 10^{-5}M

Therefore, the concentration of diluted solution is 0.034\times 10^{-5}M

3) On further dilution

M_1V_1=M_2V_2

where,

M_1 = molarity of stock solution = 0.034\times 10^{-5}M

V_1 = volume of stock solution = 3.00 ml

M_2 = molarity of diluted solution = ?

V_2 = volume of diluted solution = 25.00 ml

0.034\times 10^{-5}M\times 3.00=M_2\times 25.00

M_2=4.0\times 10^{-8}M

Therefore, the concentration of final solution is 4.0\times 10^{-8}M

5 0
3 years ago
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