Answer:
2.6 atm
Explanation:
At constant temperature, solubility of gas increases as pressure increases, Hence, they varies directly proportional.
i.e S ∝ P
where:
S₁ and P₁ are the initial solubility and pressure of the gas
S₂ and P₂ are the final solubility and pressure of the gas
Making P₂ the subject of the formula from the above equation; we have:
where; it is given from the question that:
P₁ = 1.0 atm
S₁ = 0.36 g/L
S₂ = 9.5 g/L
Replacing the values into the above equation; we have:
P₂ = 2.6 atm
∴ The pressure needed to produce an aqueous solution containing 9.5 g/L of the same gas at 0°C = 2.6 atm
The number Beryllium chloride consumed is calculated as follows
write equation for reaction
that is BeCl2 + Mg -----> MgCl2 +Be
find the moles of MgCl2 produced
moles =mass/molar mass of MgCl2
= 987.5g/95 = 10.39 moles
by use of mole ratio between BeCl2 to Mgcl2 which 1:1 therefore the moles of BeCl2 is also 10.39moles
mass of BeCl2 = moles x molar mass
that is 10.39 x80 = 831.2
Answer:
K^+(aq) + Br^-(aq) -----> KBr(aq)
Explanation:
The net ionic equation shows the actual reaction that occurs in the system. The molecular reaction equation includes the spectator ions but the net ionic equation does not include the spectator ions.
Spectator ions do not participate in the main reaction going on in the system.
Hence, for the reaction of potassium hydroxide and ammonium bromide, we have;
K^+(aq) + Br^-(aq) -----> KBr(aq)
Answer:
The relative humidity is 36%.
Explanation:
Relative humidity is the measure of ratio of actual vapor density to saturated vapor density in a given system. So there are different ways to measure the relative humidity in the atmosphere. One of the common ways is to measure using Psychrometer. In this instrument, two different thermometers are used as measuring device. One of the thermometer measures the humidity in dry air and another in wet air. So the difference of the temperature of dry and wet air bulb will be related to determine the relative humidity percentage. The formula to determine the relative humidity using this method is as below.
![Relative humidity=\frac{(e_{w}-[N*(1+0.00115*T_{w}*(T_{d}-T_{w}))])*100}{e_{d} }](https://tex.z-dn.net/?f=Relative%20humidity%3D%5Cfrac%7B%28e_%7Bw%7D-%5BN%2A%281%2B0.00115%2AT_%7Bw%7D%2A%28T_%7Bd%7D-T_%7Bw%7D%29%29%5D%29%2A100%7D%7Be_%7Bd%7D%20%7D)
Also,
![e_{d}=6.112*e^{[\frac{(17.502*T_{d} )}{(240.97+T_{d} )}]}](https://tex.z-dn.net/?f=e_%7Bd%7D%3D6.112%2Ae%5E%7B%5B%5Cfrac%7B%2817.502%2AT_%7Bd%7D%20%29%7D%7B%28240.97%2BT_%7Bd%7D%20%29%7D%5D%7D)
And,
![e_{w}=6.112*e^{[\frac{(17.502*T_{w} )}{(240.97+T_{w} )}]}](https://tex.z-dn.net/?f=e_%7Bw%7D%3D6.112%2Ae%5E%7B%5B%5Cfrac%7B%2817.502%2AT_%7Bw%7D%20%29%7D%7B%28240.97%2BT_%7Bw%7D%20%29%7D%5D%7D)
Here e =2.718, 
and 
are the temperature at dry bulb and wet bulb temperatures, respectively.
So, the relative humidity after substituting the values of Td = 2 C and Tw = -2 C is 36%.
B.
The cynobacteria were already there without the oxygen, so that rules out A, and a lot of prokaryotes were anaerobic, so that rules out C. Finally, Photosynthesis does not require oxygen. Instead, Oxygen is a waste product of it. Therefore, it cannot be D. So, we are only left with B
Hoped this helped :D
