Answer:
3, because H2 ×3 =6, and if you plug in a two in NH3 it would be equal
Answer:
a) 8.33 ml of the original stomach acid is neutralized
b) 191.67 ml of the stomach acid was neutralized
c) 249.68 ml acid would be neutralized by the original tablet
Explanation:
a) how much of the stomach acid had been neutralized in the 25 mL sample wich was titrated?
25.5 ml of a NaOH solution is equivalent to 25.00 ml of the original stomach acid
8.5 ml NaOH * (25.00 ml original stomach acid / 25.5 ml NaOH) = 8.33 ml original stomach acid
b) how much stomach acid was neutralized y the 4.3628 g tablet?
It takes 8.5 ml NaOH to neutralize 8.33 ml original acid (this is the answer for question 1)
This means the antacid neutralized = 200 ml - 8.33 ml = 191.67 ml
c) how much stomach acid would have been neutralized by the original 5.6832 g tablet
4.3628 g antacid is equivalent to 191.67 ml acid ( this is the answer for question 2)
5.6832g antacid * (191.67 ml acid / 4.3628 g antacid) = 249.68 ml acid
The answer is: volume of ammonia gas is 7.4 L.
Chemical reaction: 6NO + 4NH₃ → 5N₂ + 6H₂O.
m(NO) = 15 g; mass of nitrogen(II) oxide.
M(NO) = 30 g/mol; molar mass of nitrogen(II) oxide.
V(NH₃) = ?
n(NO) = 15 g ÷ 30 g/mol.
n(NO) = 0.5 mol; amount of nitrogen(II) oxide.
From chemical reaction: n(NO) : n(NH₃) = 6 : 4.
0.5 mol : n(NH₃) = 6 : 4.
n(NH₃) = 0.33 mol; amount of ammonia.
Vm = 22.4 L/mol; molar volume at STP.
V(NH₃) = 0.33 mol · 22.4 L/mol..
V(NH₃) = 7.4 L.
Answer;
H- (negatively charged hydrogen ion)
Explanation;
The hydrogen ion has the same electron configuration as an atom of Helium. -Hydrogen ion is formed when a hydrogen atom loses or gains an electron. A positively charged ion is formed when hydrogen atom loses an electron (remaining with zero electrons) while a negatively charged ion (H-) is formed when a hydrogen atom gains an electron thus having 2 electrons.
-Helium atom has two electrons, therefore, it is similar with an negatively charged hydrogen.
