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lutik1710 [3]
3 years ago
9

PLEASE HELP FOR 5 STAR AND BRAINLIST TYSM

Mathematics
1 answer:
victus00 [196]3 years ago
5 0

Answer:

Step-by-step explanation:

1) 792÷ 36=22

2) 1/2 ÷ 3 = 1/6

3) D

4) its 10,00 cause 7.741 x 10 = 77,410

5) the answer in decimal is 60.089

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I kinda need help thanks
Cerrena [4.2K]

Answer:

move 2 to the w×2 box and then move 8 to the anwser

4 0
3 years ago
Read 2 more answers
Subtract (-4x - 2) - (13x + 1)
sp2606 [1]

Answer:

-17x-3

Step-by-step explanation:

Distribute the negative to the second part of the equation. remove the parenthesis from the first part and then add like values.

-4x-2-13x-1

-4x-13x-2-1

-17x-3

6 0
3 years ago
What is x? <br><br> 7x + 9= 5x-3
Pani-rosa [81]

Answer:

-6

Step-by-step explanation:

7x + 9 = 5x -3

-5x -5x

2x+9=-3

-9 -9

2x=-12

divide by 2

x = -6

3 0
3 years ago
The coordinate of two point P(4,6) and Q(5,-7) then find (abicissa of P) -(abicissa of Q)
grandymaker [24]

The value of (abscissa of P) -(abscissa of Q) is -1.

The given coordinates are P(4,6) and Q(5,-7).

We need to find (abscissa of P) -(abscissa of Q).

<h3>What is abscissa?</h3>

The horizontal coordinate of a point in a planar Cartesian coordinate system that is determined by measuring parallel to the x-axis is what abscissa stands for.

Now, (abscissa of P) -(abscissa of Q)=4-5=-1

Hence, the value of (abscissa of P) -(abscissa of Q) is -1.

To learn more about abscissa visit:

brainly.com/question/1214621.

#SPJ1

7 0
3 years ago
A small craft in lake Ontario sends out a distances signal. The coordinates of the boat in trouble are (57,64). One rescue boat
KatRina [158]

Answer:

The coast guard craft will get to the distressed boat the fastest.

Step-by-step explanation:

The coordinates of boat are (57,64).

The coordinates of rescue boat are (67,83).

The  coordinates of coast guard craft are (65,46).

Both rescue crafts travel at the same rate. One of them will get to the distressed boat the faster, whose distance from the boat is least.

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The distance between boat and rescue boat is

d_1=\sqrt{(67-57)^2+(83-64)^2}=21.4709105536\approx 21.47

The distance between boat and coast guard craft is

d_2=\sqrt{(65-57)^2+(46-64)^2}=19.6977156036\approx 19.70

Since the distance between boat and coast guard craft is least, therefore coast guard craft will get to the distressed boat the fastest.

6 0
3 years ago
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