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kotegsom [21]
3 years ago
9

Consider the angle shown below with an initial ray pointing in the 3-o'clock direction that measures θ radians (where 0≤θ<2π)

. The terminal point is (1.33,−2).
What is the angle's measure (in radians)?
θ=
​

Mathematics
1 answer:
Mamont248 [21]3 years ago
6 0

Answer:

5.3 or (4217pi/2500)

Step-by-step explanation:

Create a right triangle with the coordinates provided.

We can ignore the negative sign and create the equation

tan(x) = \frac{1.33}{2}

x = 33.624

We then add 270 and x together because the coordinates are in the 4th quadrant.

angle = 303.624

To convert to radians, we multiply this number by pi/180

5.3 radians

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Find the missing side length in the right triangle. ​
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5.83

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Can you guys help me out on this? I'm still learning sign, cosign, and tangent :)
Yakvenalex [24]

Answer:

\sin d = \frac{4}{7} ; \sin e = \frac{\sqrt{33} }{7}

\cos d = \frac{\sqrt{33} }{7} ; \cos e = \frac{4}{7}

\tan d = \frac{4}{\sqrt{33} } ; \tan e = \frac{\sqrt{33} }{4}

Step-by-step explanation:

For a right angled triangle with one of its angle α (alpha) :-

  • \sin \alpha = \frac{Side \: opposite \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}
  • \cos \alpha  = \frac{Side \: adjacent \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}
  • \tan \alpha  = \frac{Side \: opposite \: to \: \alpha }{Side \: adjacent \: to \: \alpha }

__________________________________________________

According to the question ,

1) When α (alpha) = d

  • \sin d = \frac{4}{7}
  • \cos d = \frac{\sqrt{33} }{7}
  • \tan d = \frac{4}{\sqrt{33} }

2) When α (alpha) = e

  • \sin e = \frac{\sqrt{33} }{7}
  • \cos e = \frac{4}{7}
  • \tan e = \frac{\sqrt{33} }{4}

3 0
3 years ago
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Answer:

10x^2 + 12x + 14

Step-by-step explanation:

Combine like terms: 2x^2 + 8x^2 = 10x^2 , 9x + 3x = 12x , 12 + 2 = 14

In total: 10x^2 + 12x + 14

7 0
3 years ago
Read 2 more answers
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