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muminat
3 years ago
5

11) Which group of Elements have Similar chemical Properties? *

Chemistry
1 answer:
Kryger [21]3 years ago
6 0
Ca, Sr, Ba have similar chemical properties.
Explanation: They are in the same group (Alkaline Earth Metals)
You might be interested in
Determine the type of reaction: AgNO3 + Cu --> Cu(NO3)2 + Ag
guajiro [1.7K]

Explanation:

Cu + 2 AgNO3 → Cu(NO3)2 + 2 Ag

Cu is oxidized

Ag+ is reduced

Cu is the reducing agent

7 0
2 years ago
An equilibrium mixture of N2, O2and NO gases at 1500K is determined to consist of 6.4 x 10-3Mof N2, 1.7 x 10-3M O2, and 1.1 x 10
sp2606 [1]

Answer

                    Explanation:O2 = 1.7×10-3M;

N2 = 6.4×10-3M;

NO = 1.1 10-5M.

4 0
2 years ago
What two factors most affect the pitch of the sounds made by a person's vocal cords? A. the volume and health of the person's lu
dusya [7]

Answer:

The pitch of the sound a person makes is determined by several factors, including the size and tension of his or her vocal cords.

Explanation:

6 0
2 years ago
Can you pls tell me the net ironic equation of H₂²⁺(aq) + O₂²⁻(aq) + Mg²⁺(aq) + SO₃²⁻(aq) → Mg²⁺(aq)+SO²⁻₄(aq) + H₂O(l)
almond37 [142]

Answer:

H₂²⁺(aq) + O₂²⁻(aq) + SO₃²⁻(aq) → SO²⁻₄(aq) + H₂O(l)

Explanation:

H₂²⁺(aq) + O₂²⁻(aq) + Mg²⁺(aq) + SO₃²⁻(aq) → Mg²⁺(aq) + SO²⁻₄(aq) + H₂O(l)

A careful observation of the equation above, shows that the equation is already balanced.

To obtain the net ionic equation, we simply cancel Mg²⁺ from both side of the equation as shown below:

H₂²⁺(aq) + O₂²⁻(aq) + SO₃²⁻(aq) → SO²⁻₄(aq) + H₂O(l)

5 0
2 years ago
Give the half equation to show what happens to oxygen when it is rusting
ycow [4]

Answer:

½O 2 + 2e - + H 2O → 2OH.

Explanation:

Redox reactions - Higher

In terms of electrons:

oxidation is loss of electrons

reduction is gain of electrons

Rusting is a complex process. The example below show why both water and oxygen are needed for rusting to occur. They are interesting examples of oxidation, reduction and the use of half equations:

iron loses electrons and is oxidised to iron(II) ions: Fe → Fe2+ + 2e-

oxygen gains electrons in the presence of water and is reduced: ½O2 + 2e- + H2O → 2OH-

iron(II) ions lose electrons and are oxidised to iron(III) ions by oxygen: 2Fe2+ + ½O2 → 2Fe3+ + O2-

3 0
3 years ago
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