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Fynjy0 [20]
3 years ago
10

A sonar device on a ship sends ultrasound waves under the water to locate a submarine. It takes

Chemistry
1 answer:
olga55 [171]3 years ago
7 0

Answer:

3750 m

Explanation:

We must first know the speed of sound in water in order to solve this problem.

So, speed of sound in water = 1500 meters per second

Now time taken = 5 seconds

Given that;

v = 2x/t

where x is the distance below;

vt = 2x

x = vt/2

x = 1500 * 5/2

x = 3750 m

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Science doesn't make moral judgments, doesn't make aesthetic judgments, doesn't tell you how to use scientific knowledge, doesn't draw conclusions about supernatural explanations. So that's why I think it has limitations.

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3 years ago
I need help I know it isnt A
inna [77]
It is B. Thank you later please and do good on the test!
5 0
3 years ago
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If an isotope of uranium, uranium-235, has 92 protons, how many protons does the isotope uranium-28 have?
padilas [110]
92. A<span>ll </span>isotopes<span> of uranium have the same number of protons</span>
4 0
3 years ago
In a mixture of hydrogen and nitrogen gases, the mole fraction of nitrogen is 0.333. If the partial pressure of hydrogen in the
notka56 [123]

Answer:

P_T=112.4torr

Explanation:

Hello there!

In this case, since these problems about gas mixtures are based off Dalton's law in terms of mole fraction, partial pressure and total pressure, we can write the following for hydrogen, we are given its partial pressure:

P_{H_2}=x_{H_2}*P_T

And can be solved for the total pressure as follows:

P_T=\frac{P_{H_2}}{x_{H_2}}

However, we first calculate the mole fraction of hydrogen by subtracting that of nitrogen to 1 due to:

x_{H_2}+x_{N_2}=1\\\\x_{H_2}=1-0.333=0.667

Then, we can plug in to obtain the total pressure:

P_T=\frac{75.0torr}{0.667}\\\\P_T=112.4torr

Regards!

4 0
3 years ago
A sample containing 2.30 mol of Ne gas has an initial volume of 8.00 L. What is the final volume, in liters, when the following
marta [7]

Answer:

a. 4,00L

b. 16,00L

c. 12,31L

Explanation:

Avogadro's law says:

\frac{V_1}{n_1} =\frac{V_2}{n_2}

a. If initial conditions are 2,30mol and 8,00L and you lose one-half of atoms, that means you have 1,15mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{1,15mol}

<em>V₂ = 4,00L</em>

b. If initial conditions are 2,30mol and 8,00L and you add 2,30mol, that means you have 4,60mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{4,60mol}

<em>V₂ = 16,00L</em>

c. 25,0g of Ne are:

25,0g × (1mol / 20,1797g) = 1,24 moles of Ne. That means you have 2,30mol - 1,24mol = 3,54mol of Ne

\frac{8,00L}{2,30mol} =\frac{V_2}{3,54mol}

<em>V₂ = 12,31L</em>

I hope it helps!

6 0
3 years ago
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