Answer:
2621.75 j heat is required to increase the temperature 25.5°C to 46°C.
Explanation:
Given data:
Mass of sample = 142.1 g
Initial temperature = 25.5°C
Final temperature = 46°C
Specific heat capacity of Al = 0.90 J/g.°C
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 46°C - 25.5°C
ΔT = 20.5°C
Q = 142.1 × 0.90 J/g.°C × 20.5°C
Q = 2621.75 j
Thus, 2621.75 j heat is required to increase the temperature 25.5°C to 46°C.
If the graph has no trend which means almost constant, it indicates that the dependent variables will not change when the independent variables change.
The answer will be (4) HI because the greater the difference of the bonds in electronegativity, the more polar a bond is.
When air is hot, the the particles move much faster and when the air is cold the particles slow down as they are condensing
They are important because they are the electrons that help the atom to bond with another atom. They are in the outer most shell. ☺️
