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Norma-Jean [14]
3 years ago
9

Which angles are adjacent to each other?

Mathematics
2 answers:
Goshia [24]3 years ago
5 0

Answer:

Two angles are Adjacent when they have a common side and a common vertex (corner point) and don't overlap. Because: they have a common side (line CB) they have a common vertex (point B)

IN STEAD OF IT SAYING POINT A AND B IN YOUR CASE IT WOULD BE 7

AND 9 IN YOUR CASE???

Step-by-step explanation:

kherson [118]3 years ago
4 0

Answer:

angle 9 and angle 1 is the right answer.

please thanks and follow me.

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On which attempts was his time less than 60 seconds?
adelina 88 [10]

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4 6 and 7?

Step-by-step explanation:

all you have to do is find 60 sec mark and all attempts bellow it are below 60 sec or under 60 sec

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3 years ago
F(x) = 6 • (0.4)x. then determine which answer choice matches the graph you drew. (Please help)
ladessa [460]

Answer:B

Step-by-step explanation: It’s a decay function

6 0
4 years ago
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a particle moves along the x-axis so that anytime t comma measured in seconds it's position is given by...​
Natali5045456 [20]

Given the position function <em>s(t)</em>, you can get the acceleration function by differentiating <em>s</em> twice:

velocity = <em>s'(t)</em> = -5 sin(<em>t </em>) + 3 cos(3<em>t</em> )

acceleration = <em>s''(t)</em> = -5 cos(<em>t</em> ) - 9 sin(3<em>t</em> )

Then when <em>t</em> = <em>π</em>, the particle's acceleration is

<em>s''(π)</em> = -5 cos(<em>π</em>) - 9 sin(3<em>π</em>)

… = -5 • (-1) - 9 • 0 = 5

7 0
3 years ago
Evaluate the following<br> average rate of change of<br> f from x=0 to x=4 is ?
nekit [7.7K]

Answer:

Step-by-step explanation:

-5/4

6 0
2 years ago
In Problems 23–30, use the given zero to find the remaining zeros of each function
Talja [164]

Answer:

x =  2i, x = -2i and x = 4 are the roots of given polynomial.

Step-by-step explanation:

We are given the following expression in the question:

f(x) = x^3 - 4x^2+ 4x - 16

One of the zeroes of the above polynomial is 2i, that is :

f(x) = x^3 - 4x^2+ 4x - 16\\f(2i) = (2i)^3 - 4(2i)^2+ 4(2i) - 16\\= -8i+ 16+8i-16 = 0

Thus, we can write

(x-2i)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16

Now, we check if -2i is a root of the given polynomial:

f(x) = x^3 - 4x^2+ 4x - 16\\f(-2i) = (-2i)^3 - 4(-2i)^2+ 4(-2i) - 16\\= 8i+ 16-8i-16 = 0

Thus, we can write

(x+2i)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16

Therefore,

(x-2i)(x+2i)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16\\(x^2 + 4)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16

Dividing the given polynomial:

\displaystyle\frac{x^3 - 4x^2 + 4x - 16}{x^2+4} = x -4

Thus,

(x-4)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16

X = 4 is a root of the given polynomial.

f(x) = x^3 - 4x^2+ 4x - 16\\f(4) = (4)^3 - 4(4)^2+ 4(4) - 16\\= 64-64+16-16 = 0

Thus, 2i, -2i and 4 are the roots of given polynomial.

4 0
3 years ago
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