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NemiM [27]
3 years ago
7

Evaluate 6n-2 for n=4.

Mathematics
1 answer:
kvasek [131]3 years ago
4 0

Answer:

6n-2 = 22

Step-by-step explanation:

n = 4

6(4)-2

24-2

22

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An acute angle, θ, is in a right triangle such that cos θ = 12/13. What is the Value of csc θ? (100 Points!)
Hatshy [7]

Answer:

csc θ = 13/12

Step-by-step explanation:

cos θ = 12/13

Formula: cos θ = 1/cscθ

Its just the reciprocal.

solve:

1/csc θ = 12/13

csc θ = 13/12

4 0
2 years ago
Read 2 more answers
What is the simplified form of the following expression?
geniusboy [140]

Answer:

242

Step-by-step explanation:

Simplify the following:

11 ((9^2 - 5^2)/2^2 + 8)

Hint: | Evaluate 2^2.

2^2 = 4:

11 ((9^2 - 5^2)/4 + 8)

Hint: | Evaluate 5^2.

5^2 = 25:

11 ((9^2 - 25)/4 + 8)

Hint: | Evaluate 9^2.

9^2 = 81:

11 ((81 - 25)/4 + 8)

Hint: | Subtract 25 from 81.

| 7 | 11

| 8 | 1

- | 2 | 5

| 5 | 6:

11 (56/4 + 8)

Hint: | Reduce 56/4 to lowest terms. Start by finding the GCD of 56 and 4.

The gcd of 56 and 4 is 4, so 56/4 = (4×14)/(4×1) = 4/4×14 = 14:

11 (14 + 8)

Hint: | Evaluate 14 + 8 using long addition.

| 1 |  

| 1 | 4

+ | | 8

| 2 | 2:

11×22

Hint: | Multiply 11 and 22 together.

| 2 | 2

× | 1 | 1

| 2 | 2

2 | 2 | 0

2 | 4 | 2:

Answer: 242

3 0
3 years ago
Need help on this one please
Archy [21]
The answer is A because there are only acute angles
3 0
3 years ago
Need step-by-step. Please answer correctly. This determines what grade I get. I will mark brainliest to the first person who ans
tatyana61 [14]

Answer:

  3√3

Step-by-step explanation:

For the problem shown here, your answer 3√3 is correct.

When there is a radical by itself in the denominator, you multiply numerator and denominator by a radical that results in the product being rational. For a square root, that will usually be the same square root:

  \dfrac{9}{\sqrt{3}}=\dfrac{9}{\sqrt{3}}\cdot\dfrac{\sqrt{3}}{\sqrt{3}}=\dfrac{9\sqrt{3}}{3}=\boxed{3\sqrt{3}}

__

If the problem has a sum in the denominator involving a square root, then you multiply numerator and denominator by the conjugate of that sum (the sum with the sign changed). This uses the special product "difference of squares" to eliminate the radical term.

<u>Example</u>:

  \dfrac{9}{2-\sqrt{3}}=\dfrac{9}{2-\sqrt{3}}\cdot\dfrac{2+\sqrt{3}}{2+\sqrt{3}}=\dfrac{9(2+\sqrt{3})}{2^2-(\sqrt{3})^2}=\dfrac{18+9\sqrt{3}}{4-3}\\\\=\boxed{18+9\sqrt{3}}

__

It is easy to demonstrate that none of the offered choices for this problem has the same value as 9/√3.

9/√3 ≈ 5.196. Offered choices have values of about 4.798, 1.732, 6.681, 23.196 -- none even close.

Please discuss this question with your teacher.

3 0
3 years ago
Drugs+Kids=..................<br><br> Very tough question guys
ycow [4]

Answer:

= desaster

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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