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Vedmedyk [2.9K]

3 years ago

13

Mr. Mendez buys his wife a coffee machine on Amazon. The coffee machine’s starting price is $49. The coffee machine is 5% off. T

here is an additional 10% service fee added for shipping and handling. How much will Mr. Mendez pay in total?

1 answer:

iren [92.7K]3 years ago

7 0

She had coffee about like 4

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Bob wants to buy a TV that cost $500 plus 8% tax. He is getting a bonus of $45 and a birthday gift of $85 which he plans to use

Genrish500 [490]

Answer:

He needs to work for 40 whole hours

Step-by-step explanation:

In this question, we are tasked with calculating the amount a Tv will cost Bob in terms of the number of hours he needs to work.

Let’s look at the total cost he has to pay.

a. $500

b. 8% tax = 8/100 * 500 = $40

c. He is paying 2 bills of $35 each making a total of 2 * $35 = $70

The total amount he is to pay is thus; 500 + 40 + 70 = $610

Let’s look at his income ;

a. Bonus $45

b. Birthday gift $85

The total amount of money he has asides his salary to offset the bill is 45 + 85 = $130

The balance to pay from his salary would be $610 - $130 = $480

The number of hours he has to work since he earns $12 per hour would be 480/12 = 40 hours of work

5 0

3 years ago

Read 2 more answers

Try the numbers 22, 23, 24, 25 in the equation 4/3 = 32/d to test whether any of them is a solution. a. 23 is a solution. c. 24

S_A_V [24]

Answer:

c. 24 is a solution

Step-by-step explanation:

Given equation:

$\frac{4}{3}=\frac{32}{d}$

To test the numbers 22, 23, 24, 25 for the solution.

Solution:

In order to test the given number for the solution, we will plugin each number in the unknown variable $d$ and see if it satisfies the equation.

1) $d=22$

$\frac{4}{3}=\frac{32}{22}$

Reducing fraction to simplest form by dividing the numerator and denominator by their G.C.F.

$\frac{4}{3}=\frac{32\div 2}{22\div 2}$

$\frac{4}{3}=\frac{16}{11}$

The above statement can never be true and hence 22 is not a solution.

2) $d=23$

$\frac{4}{3}=\frac{32}{23}$

The fractions can no further be reduced.

The statement can never be true and hence 23 is not a solution.

3) $d=24$

$\frac{4}{3}=\frac{32}{24}$

Reducing fraction to simplest form by dividing the numerator and denominator by their G.C.F.

$\frac{4}{3}=\frac{32\div 8}{24\div 8}$

$\frac{4}{3}=\frac{4}{3}$

The above statement is always true and hence 24 is a solution.

4) $d=25$

$\frac{4}{3}=\frac{32}{25}$

The fractions can no further be reduced.

The statement can never be true and hence 25 is not a solution.

4 0

3 years ago

I need help fast... if answered Correctly I will mark brainliest

Lesechka [4]

9514 1404 393

Answer:

(-5,1)

Step-by-step explanation:

To eliminate x, multiply the first equation by 3 and add 2 times the second equation.

3(-2x +7y) +2(3x -4y) = 3(17) +2(-19)

-6x +21y +6x -8y = 51 -38

13y = 13

y = 1 . . . . . matches the third answer choice

(x, y) = (-5, 1)

5 0

3 years ago

John is gliding along on his scooter at a speed of 2.8 m/s when

user100 [1]

Answer:

18.67 m/s²

Step-by-step explanation:

a = ∆v/ t

a= v - u/t

a = 2.8 - 0 / 0.15

a = 2.8 / 0.15

a = 18.67 m/s²

3 0

3 years ago

In a simple random sample of 14001400 young people, 9090% had earned a high school diploma. Complete parts a through d below.

ratelena [41]

Answer:

(a) The standard error is 0.0080.

(b) The margin of error is 1.6%.

(c) The 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

(d) The percentage of young people who earn high school diplomas has increased.

Step-by-step explanation:

Let <em>p</em> = proportion of young people who had earned a high school diploma.

A sample of <em>n</em> = 1400 young people are selected.

The sample proportion of young people who had earned a high school diploma is:

$\hat p=0.90$

(a)

The standard error for the estimate of the percentage of all young people who earned a high school diploma is given by:

$SE_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}$

Compute the standard error value as follows:

$SE_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=\sqrt{\frac{0.90(1-0.90)}{1400}}\\$

$=0.008$

Thus, the standard error for the estimate of the percentage of all young people who earned a high school diploma is 0.0080.

(b)

The margin of error for (1 - <em>α</em>)% confidence interval for population proportion is:

$MOE=z_{\alpha/2}\times SE_{\hat p}$

Compute the critical value of <em>z</em> for 95% confidence level as follows:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Compute the margin of error as follows:

$MOE=z_{\alpha/2}\times SE_{\hat p}$

$=1.96\times 0.0080\\=0.01568\\\approx1.6\%$

Thus, the margin of error is 1.6%.

(c)

Compute the 95% confidence interval for population proportion as follows:

$CI=\hat p\pm MOE\\=0.90\pm 0.016\\=(0.884, 0.916)\\\approx (88.4\%,\ 91.6\%)$

Thus, the 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

(d)

To test whether the percentage of young people who earn high school diplomas has increased, the hypothesis is defined as:

<em>H₀</em>: The percentage of young people who earn high school diplomas has not increased, i.e. <em>p</em> = 0.80.

<em>Hₐ</em>: The percentage of young people who earn high school diplomas has not increased, i.e. <em>p</em> > 0.80.

Decision rule:

If the 95% confidence interval for proportions consists the null value, i.e. 0.80, then the null hypothesis will not be rejected and vice-versa.

The 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

The confidence interval does not consist the null value of <em>p</em>, i.e. 0.80.

Thus, the null hypothesis is rejected.

Hence, it can be concluded that the percentage of young people who earn high school diplomas has increased.

8 0

3 years ago