Answer:
The velocity of motion at which the occupants of the car appear to weigh 20% less than their normal weight is approximately 19.81 m/s
Explanation:
The given parameters are;
The curvature of the hill, r = 200 m
Due to the velocity, v, the occupants weight = 20% less than the normal weight
The outward force of an object due to centripetal (motion) force is given by the following equation;
Where;
r = The radius of curvature of the hill = 200 m
Given that the weight of the occupants, W = m × g, we have;
v = √(0.2 × g × r)
By substitution, we have;
v = √(0.2 × 9.81 × 200) ≈ 19.81
The velocity of motion at which the occupants of the car appear to weigh 20% less than their normal weight ≈ 19.81 m/s.
As per Newton's 2nd law
we know that
it is product of mass and acceleration
here we know that
also we know that
so from above equation we have
so the force here will be 10020 N
Answer:
Explanation:
<u>Given the following data;</u>
Initial velocity = 0 (since the stone is starting from rest).
Final velocity = 32 m/s
Acceleration = g = 10 m/s²
Time = 3.2 seconds
To show that the speed of the stone when it hits the ground is 32 m/s, we would use the first equation of motion;
Where;
- V is the final velocity.
- U is the initial velocity.
- a is the acceleration.
- t is the time measured in seconds.
Substituting into the formula, we have;
<em>Proven: 32 m/s = 32 m/s</em>
We will individually calculate the Kinetic Energy of each of the carts and compare them
<u>Cart A:</u>
m = 1 kg , v = 3 m/s
KE = 1/2 mv²
KE = 9/2 = 4.5 J
<u>Cart B:</u>
m = 3 kg , v = 1m/s
KE = 1/2 mv²
KE = 3/2 = 1.5 J
<u>Cart C:</u>
m = 3 kg , v = 2 m/s
KE = 1/2 mv²
KE = 6 J
<u>Cart D:</u>
m = 4 kg , v = 2 m/s
KE = 1/2 mv²
KE = 2 J
Therefore, Cart C has the most Kinetic energy
