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3 years ago

What is the force on a 1670kg elevator accelerating at 6m/s square?

Physics

1 answer:

marshall27 [118]3 years ago

7 0

As per Newton's 2nd law

we know that

$F = ma$

it is product of mass and acceleration

here we know that

$m = 1670 kg$

also we know that

$a = 6 m/s^2$

so from above equation we have

$F = 1670 * 6$

$F = 10020 N$

so the force here will be 10020 N

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A rock is projected from the edge of the top of a building with an initial velocity of 12.2 m/s at an angle of 73° above the hor

Brrunno [24]

Answer:

7 s

Explanation:

u = Initial velocity of rock = 12.2 m/s

$\theta$ = Angle of throw = $73^{\circ}$

x = Displacement in x direction = 25 m

Displacement in x direction is given by

$x=u\cos\theta t\\\Rightarrow t=\dfrac{x}{u\cos\theta}\\\Rightarrow t=\dfrac{25}{12.2\times \cos73^{\circ}}\\\Rightarrow t=7\ \text{s}$

Time taken to reach the ground is 7 s.

4 0

3 years ago

An insulated lamp bulb is on the bottom of a swimming pool at a point 2.5 m from a wall; the pool is 2.5 m deep and filled to th

pashok25 [27]

Answer:

option A

Explanation:

given,

lamp position from pool wall = 2.5 m

height of the pool = 2.5 m

now,

$tan \theta = \dfrac{P}{B}$

$\theta =tan^{-1}(\dfrac{2.5}{2.5})$

$\theta =45^0$

from the triangle

θ = i = 45°

using Snell's law

n₁ sin i = n₂ sin r

n₁ =4/3 n₂ = 1

now,

$\dfrac{sin r}{sin i}=\dfrac{n_1}{n_2}$

$\dfrac{sin r}{sin 45^0}=\dfrac{\dfrac{4}{3}}{1}$

$sin r=\dfrac{1}{\sqrt{2}}\times \dfrac{4}{3}$

r = sin⁻¹(0.9428)

r = 70.5°

hence, the correct answer is option A

8 0

4 years ago

The mass of the Moon is 7.35 x 1022 kg, while that of Earth is 5.98 x 1024 kg. The average distance from the center of the Moon

Kryger [21]

Answer:

aaa

Explanation:

$m_e$ = Mass of the Earth = 5.98 × 10²⁴ kg

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

$r_1$ = Distance from the center of the Moon to the center of Earth = 6371000 m

$r_2$ = Distance from the center of the earth center to sun center

$m_m$ = Mass of moon = $7.35\times 10^{22}\ kg$

M = Mass of sun = $1.989\times 10^{30}\ kg$

$F_1=G\frac{m_em_m}{r_1^2}\\\Rightarrow F_1=6.67\times 10^{-11}\frac{5.98\times 10^{24}\times 7.35\times 10^{22}}{(384000000)^2}\\\Rightarrow F_1=1.988\times 10^{20}\ N$

$F_2=G\frac{Mm_e}{r_1^2}\\\Rightarrow F_2=6.67\times 10^{-11}\frac{5.98\times 10^{24}\times 1.989\times 10^{30}}{(149.6\times 10^9+6371000+695.51\times 10^6)^2}\\\Rightarrow F_2=3.511\times 10^{22} N$

$\frac{F_1}{F_2}=\frac{1.988\times 10^{20}}{3.511\times 10^{22}}\\\Rightarrow \frac{F_1}{F_2}=0.00566\\\Rightarrow F_1=F_20.00566$

Hence the force of moon on earth is 0.00566 times the force of earth on moon center to center

4 0

4 years ago

Anya recorded the temperatures of four different smooth materials after they were placed under a heat lamp for thirty minutes. A

bekas [8.4K]

Answer:

Explanation:

4 0

4 years ago

Read 2 more answers

Identify forces between two objects which are inversely proportional to the square of the distance between them. i. nuclear forc

nikdorinn [45]

The force between two celestial bodies is a Newtonian gravitational force.
It is also called Newton's law of universal gravitation. We can write it down mathematically in the following way:
$F=G \frac{ m_{1} m_{2} }{ r^{2}}$
We can see from this formula that gravitational force is <span>inversely proportional to the square of the distance between bodies.
The electrostatic force between two charges is Coulombs force. We can write it down like this:
</span> $F= k_{e} \frac{ q_{1} q_{2} }{ r^{2}}$
This force is also inversely proportional to the square of the distance between interacting particles.
The nuclear force is a little bit more complicated. It can be expressed using the so-called Yukawa potential, which has the following form:
$V_{y} =- g^{2} \frac{ e^{-ur} }{r}$
This interaction does not follow the inverse-square law.
The final answer should be 8.

3 0

3 years ago