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n200080 [17]
3 years ago
15

The closer together a magnets field lines are,

Physics
1 answer:
elena55 [62]3 years ago
4 0
The stronger they will be
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A student takes the elevator up to the fourth floor to see her favorite physics instructor. She stands on the floor of the eleva
never [62]

Answer:

N = 1364 N

Explanation:

given data

accelerate upward = 5.70 m/s²

mass = 88.0 kg

solution

normal force is in upward direction so, weight of the student in downward direction and acceleration is in upward direction so formula is express as

N - mg = ma        ...........................1

N = m × (g+a)

put here value

N = 88.0 × (9.8 + 5.70)

N = 1364 N

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3 years ago
What are the two types of physical fitness?<br>​
Marina86 [1]

<em><u>your </u></em><em><u>question</u></em><em><u>:</u></em><em><u> </u></em>

<em>What are the two types of physical fitness?</em>

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4 0
3 years ago
Which scenario would be classified as a conceptual model
den301095 [7]

Answer:

Heyo! (Ish Mash Potato) XD

Explanation:

A conceptual model is a representation of a system, made of the composition of concepts which are used to help people know, understand, or simulate a subject the model represents. It is also a set of concepts. Some models are physical objects; for example, a toy model which may be assembled, and may be made to work like the object it represents.

Hope Mr. Mash Potato Helped!!!

3 0
3 years ago
Read 2 more answers
Which of the following equations can be used to directly calculate an object's impulse?
Iteru [2.4K]
I believe the answer is B
7 0
4 years ago
You throw a 3.00 N rock vertically into the air from ground level. You observe that when it is 16.0 m above the ground, it is tr
Morgarella [4.7K]

Answer:

The final speed of the stone as it lift the ground is 23.86 m/s.            

Explanation:

Given that,

Force acting on the rock, F = 3 N

Distance, d = 16 m

Initial speed of the stone, u = 22 m/s

We need to find the rock's speed just as it left the ground. It can be calculated using work energy theorem as :

W=\Delta E\\\\W=\dfrac{1}{2}m(v^2-u^2)\\\\Fd=\dfrac{1}{2}m(v^2-u^2)\\\\v^2=\dfrac{2Fd}{m}+u^2\\\\v^2=\dfrac{2mgd}{m}+u^2\\\\v^2=2\times 9.8\times 16+(16)^2\\\\v=23.86\ m/s

So, the final speed of the stone as it lift the ground is 23.86 m/s.                                                    

4 0
3 years ago
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