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stiv31 [10]
3 years ago
6

Which cart has the greatest kinetic energy?

Physics
1 answer:
Lyrx [107]3 years ago
3 0

We will individually calculate the Kinetic Energy of each of the carts and compare them

<u>Cart A:</u>

m = 1 kg  ,   v = 3 m/s

KE = 1/2 mv²

KE = 9/2 = 4.5 J

<u>Cart B:</u>

m = 3 kg  ,  v = 1m/s

KE = 1/2 mv²

KE = 3/2 = 1.5 J

<u>Cart C:</u>

m = 3 kg   ,   v = 2 m/s

KE = 1/2 mv²

KE = 6 J

<u>Cart D:</u>

m = 4 kg   ,   v = 2 m/s

KE = 1/2 mv²

KE = 2 J

Therefore, Cart C has the most Kinetic energy

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Which of the following statements best explains why liquid water is NOT found on Jupiter?
agasfer [191]

Answer:

The planet lacks a solid surface and the temperature is too low

Explanation:

Jupiter does not have solid surface as it is made up of swirling gases, mainly hydrogen(90%) and helium(~10%). The swirl comes from massive wind with speed of 335 miles/hour. The temperature in cloud of Jupiter is 145°C which is too low for water to remain in liquid state as the temperature range for liquid water is 0°C to 100°C.

6 0
3 years ago
If the graph shown is a position-time graph of an object moving at constant velocity, what is the velocity of the object? Assume
belka [17]

Answer:

C.) v = 50 m/s

Explanation:

The relationship between position vs. time graph and velocity is that the derivative (slope) of the position vs. time graph gives you velocity. In other words, find the slope to get the velocity.

Select two arbitrary points. I'll choose (3s, 225m) and (0s, 75m).

Now use the slope equation:

v = \frac{y_{2} - y_{1} }{x_{2} - x_{1}} =\frac{225 - 75}{3-0} = 50 m/s

v = 50 m/s

Hopes this helps!

5 0
3 years ago
A resistor of 5 Ω is placed in a circuit. The voltage drop across the resistor is 12 V. What is the current through the resistor
Kaylis [27]
<span>Data:

</span>R = 5 Ω
U = 12 V
i = ?
<span>
Formula:

</span>U = R*i → i =  \frac{U}{R}<span>

Solving:

</span>i = \frac{U}{R}
i = \frac{12}{5}
\boxed{i = 2.4A}

Answer:

<span>The current through the resistor is 2.4 Amperes</span><span>

</span>
5 0
3 years ago
A 1.10 kg box slides down a rough incline plane from a height h of 1.75 m. The box had a speed of 2.99 m/s at the top and a spee
madam [21]

Answer:

20.18 J

Explanation:

We are given that

Mass of bx=m=1.1 kg

Height=h=1.75 m

Initial speed of box=u=2.99 m/s

Final speed,v=2.56 m/s

We have to find the mechanical energy lost due to friction.

Energy at top=K.E+P.E=\frac{1}{2}mu^2+mgh=\frac{1}{2}(1.1)(2.99)^2+1.1\times 9.8\times 1.75=23.78 J

Where g=9.8 m/s^2

At bottom,h'=0

Energy at bottom=\frac{1}{2}mv^2+mgh'=\frac{1}{2}(1.1)(2.56)^2+0=3.6 J

Energy lost=Energy(Top)-Energy(bottom)=23.78-3.6=20.18 J

5 0
3 years ago
In a science museum, a 110 kg brass pendulum bob swings at the end of a 13.9 m -long wire. the pendulum is started at exactly 8:
saw5 [17]

The number of oscillations completed by the pendulum is 2736.

The amplitude of the pendulum is 3.47 m.

The given motion is an underdamped motion. So its frequency will be similar to that of a simple harmonic motion.

The frequency of oscillation is defined as the number of oscillations completed in unit time. It is calculated using the formula.

f=(1/2π)*√(l/g)

where f is the frequency, l is the length of the pendulum, and g is the acceleration due to gravity.

Given the length of the wire l=13.9 m and acceleration due to gravity g=9.8 m/s^2. The frequency of oscillation is:

f=(1/(2*3.14)) * √(13.9/9.8)

f=0.19 Hz (approximately)

Since the pendulum started oscillating at 8:00 am, 4 hours has been passed when it shows 12:00 pm. So time t=4 hours or t=4*3600. Hence t=14400 s. The total number of oscillations is then given by the formula,

n=ft

where n is the number of oscillations.

n=0.19*14400=2736.

In damping motion, the amplitude of the pendulum decreases with time. The amplitude of the pendulum is given by the formula,

A' = A exp (-b*t)

where A' is the amplitude after time t, A is the initial amplitude, b is the damping constant, and t is the time.

Here A=1.2 m, b=0.010 kg/s and t=14400 s.

A' = 1.2 exp (-0.010*14400)

A'=3.47 m (approximately)

Learn more about amplitude.

brainly.com/question/21632362

#SPJ4

5 0
2 years ago
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