All categories

2 years ago

This is part 2 to my last question, i think it was incorrect im sorry

Mathematics

2 answers:

skelet666 [1.2K]2 years ago

5 0

Denominator is correct
Hope that helped

Tanzania [10]2 years ago

3 0

Answer:

ELLO

uhhh yeah we helped each other one this lol

You might be interested in

Adam bought A new pair of baseball cleats for $65 the sales tax is 5.5% what is the total cost in dollars that Adam will pay

Dmitry [639]

(65×5.5%)+65 = 68.575

8 0

3 years ago

Points J and K lie in plane H.

Vlad [161]

Answer: 1

Step-by-step explanation:

From the given picture, it can be seen that there is a plane H on which two pints J and K are located.

One of the Axiom in Euclid's geometry says that "Through any given two points X and Y, only one and only one line can be drawn "

Therefore by Axiom in Euclid's geometry , for the given points J and K in plane H , only one line can be drawn through points J and K.

6 0

3 years ago

Read 2 more answers

A.4 B.3 C.2 D.1 Help please

vazorg [7]

The number of exports is GREATER than the number of imports if the bar for exports (pink) is TALLER than the bar for imports (blue). It appears that happens only on Friday.

3 0

3 years ago

What is 2/5-3/10 equal to

Ilia_Sergeevich [38]

Answer:

1/10

Step-by-step explanation:

2/5=4/10

4/10-3/10=1/10

7 0

3 years ago

Use the identity (x+y)(x2−xy+y2)=x3+y3 to find the sum of two numbers if the product of the numbers is 10, the sum of the square

professor190 [17]

Answer:

The sum of two numbers is 7.

Step-by-step explanation:

Given : the product of the numbers is 10, the sum of the squares of the numbers is 29, and the sum of the cubes of the numbers is 133.

Using identity $(x+y)(x^2-xy+y^2)=x^3+y^3$ and given details, we have to find the sum of two numbers.

Since, given that the product of the numbers is 10 that is $xy=10$

Also, given the sum of the squares of the numbers is 29 that is $x^2+y^2=29$

and the sum of the cubes of the numbers is 133 that is $x^3+y^3=133$

Using, the given identity $(x+y)(x^2-xy+y^2)=x^3+y^3$ ,

Substitute, the given values, we have,

$(x+y)(29-10)=133$

Simplify , we get,

$(x+y)(19)=133$

Divide both side by 19, we have,

$(x+y)=7$

Thus, the sum of two numbers is 7.

7 0

3 years ago

Read 2 more answers