To make calculation easier, we first multiply
1.35 × 100 = 135
then we need to find how many groups of 5 are there in 135.
to do so, we simply take
135 ÷ 5 = 27
therefore, the answer is <u>27.</u>
You have to check which of the following expressions is the rational exponent expression of third root of 4n, or mathematically, ![\sqrt[3]{4n} .](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B4n%7D%20.%20)
Consider all cases:
A. ![(4n)^3=4^3\cdot n^3=64n^3\neq\sqrt[3]{4n} .](https://tex.z-dn.net/?f=%20%284n%29%5E3%3D4%5E3%5Ccdot%20n%5E3%3D64n%5E3%5Cneq%5Csqrt%5B3%5D%7B4n%7D%20.%20%20)
B. ![3n^4\neq \sqrt[3]{4n} .](https://tex.z-dn.net/?f=%203n%5E4%5Cneq%20%5Csqrt%5B3%5D%7B4n%7D%20.%20%20)
C. quantity of 4n to the one third power is ![(4n)^{\frac{1}{3} }=\sqrt[3]{4n}](https://tex.z-dn.net/?f=%20%284n%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%20%7D%3D%5Csqrt%5B3%5D%7B4n%7D%20)
(by the definition of rational power).
D. 4 times n to the one third power is ![4\cdot n^{\frac{1}{3} }=4\sqrt[3]{n}\neq \sqrt[3]{4n} .](https://tex.z-dn.net/?f=%204%5Ccdot%20n%5E%7B%5Cfrac%7B1%7D%7B3%7D%20%7D%3D4%5Csqrt%5B3%5D%7Bn%7D%5Cneq%20%5Csqrt%5B3%5D%7B4n%7D%20.%20%20)
Answer: correct choice is C.
Answer:
$2,975
Step-by-step explanation:
Discount = Original Price x Discount %/100
Discount = 3500 × 15/100
Discount = 3500 x 0.15
You save = $525.00
Final Price = Original Price - Discount
Final Price = 3500 - 525
Final Price = $2,975.00
Answer:
b. (1, 3, -2)
Step-by-step explanation:
A graphing calculator or scientific calculator can solve this system of equations for you, or you can use any of the usual methods: elimination, substitution, matrix methods, Cramer's rule.
It can also work well to try the offered choices in the given equations. Sometimes, it can work best to choose an equation other than the first one for this. The last equation here seems a good one for eliminating bad answers:
a: -1 -5(1) +2(-4) = -14 ≠ -18
b: 1 -5(3) +2(-2) = -18 . . . . potential choice
c: 3 -5(8) +2(1) = -35 ≠ -18
d: 2 -5(-3) +2(0) = 17 ≠ -18
This shows choice B as the only viable option. Further checking can be done to make sure that solution works in the other equations:
2(1) +(3) -3(-2) = 11 . . . . choice B works in equation 1
-(1) +2(3) +4(-2) = -3 . . . choice B works in equation 2
Answer:
ASA
Step-by-step explanation:
none needed [=
