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2 years ago

12

Kevin spends $11.25 on lunch every week during the school year. If there are 35.5 weeks during the school year, how much does Ke

vin spend on lunch over the entire school year?

1 answer:

ASHA 777 [7]2 years ago

7 0

Answer:

399.37

Step-by-step explanation:

multiply the amount each week by the amount of weeks to get the answer :)

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If CDEF is a kite, CD =15 find CG

SpyIntel [72]

Answer:

Step-by-step explanation:

CD = 15, so we have the hypotenuse.

DF = 18, but we can find a leg by 18/2 which is 9

using our pyth. theorem, 15^2=9^2+CG^2

CG = 12

Hope this helped

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2 years ago

In a group of 30 people, 10 drink milk but not tea 5 drink tea

Firlakuza [10]

Answer:

2

Step-by-step explanation:

10 + 13 + 5 = 28 who drink either, or, or neither

30 - 28 = 2

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3 years ago

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Does the point (-4, 2) lie inside or outside or on the circle x^2 + y^2 = 25?

d1i1m1o1n [39]

Given equation of the Circle is ,

$\sf\implies x^2 + y^2 = 25$

And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,

$\sf\implies (x-0)^2 +( y-0)^2 = 5 ^2$

Here we can say that ,

• Radius = 5 units

• Centre = (0,0)

Finding distance between the two points :-

$\sf\implies Distance = \sqrt{ (0+4)^2+(2-0)^2} \\\\\sf\implies Distance = \sqrt{ 16 + 4 } \\\\\sf\implies Distance =\sqrt{20}\\\\\sf\implies\red{ Distance = 4.47 }$

Here we can see that the distance of point from centre is less than the radius.

Hence the point lies within the circle .

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2 years ago

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the hypotenuse of a 45-45-90 triangle has a length of 10 units. what is the length of one of its legs?

SIZIF [17.4K]

When a triangle is a 45-45-90 triangle, the following rules apply:

-the 2 legs are equal lengths
- the length of the hypotenuse is: the square root of 2 x the length of a leg.
- the length of the leg is: hypotenuse divided by the square root of 2.

if the hypotenuse is 10, then 10 divided by the square root of 2 is how you find the leg.
the square root of 2 is <span>1.41421356237.
10 divided by </span>1.41421356237 is <span>7.07106781188, which can be rounded to about 7.1. The length of one leg is about 7.1 units!</span>

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3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Clarge%5Cfrak%7B%20%5Corange%7B%20Question%7D%7D" id="TexFormula1" title=" \large\frak{ \

SVEN [57.7K]

Answer:

$\boxed{\sf distance \: between \: the \: objects \: \: is \: 2.5 \: cm}$

Step-by-step explanation:

According to universal law of gravitation every object in the universe attracts every other particles that surrounds it with a force which is inversely proportional to the square of their distance of separation & directly proportional to

the product of their masses, given by standard formula.

$A = G \cdot \frac{m_1.m_2}{ {d}^{2} }$

where A,d & G are force of attraction, distance of separation & proportionality constant respectively.

<em>Given:</em>

A1 = 2 units

d1= 5 cm

A2 = 8 units

<em>To find:</em>

Distance of separation when the force of attraction is 8 units d2 = ?

<em>Solution:</em>

Substituting the given values in above at each point,

$A_1 = G \cdot \frac{m_1.m_2}{ {d_1}^{2} } \\ 2 = G \cdot \frac{m_1.m_2}{ {5}^{2} } \\ \sf similarly \: at \: second \: point \: of \: attraction \\ A_2 = G \cdot \frac{m_1.m_2}{ {d_2}^{2} } \\ 8 = G \cdot \frac{m_1.m_2}{ {d_2}^{2} } \\ \sf \: \: dividing \: both \: of \: the \: equation \\ \frac{2}{8} = \frac{G \cdot \frac{m_1.m_2}{ {5}^{2} }}{G \cdot \frac{m_1.m_2}{ {d_2}^{2} } } \\ \sf \: G \: m_1 and \: m_2 \: are \: \: constant \: hence \\ \sf they \: can \: be \: cancelled \: out \\ \frac{2}{8} = \frac{ \frac{1}{ {5}^{2} } }{ \frac{1}{ {d_2}^{2} } } \\ \sf rearranging \: above \: equation \\ \frac{1}{4} = \frac{{d_2}^{2} }{ {5}^{2} } \\ {d_2}^{2} = \frac{ {5}^{2} }{4 } \\ {d_2}^{2} = \frac{25}{4} \\ {d_2}^{2} = 6.25 \\ \sqrt{{d_2}^{2} } = \sqrt{6.25} \\ \boxed{ \sf{d_2} = 2.5 \: cm}$

<em>Answer:</em><em> </em><em>the distance between the two </em><em>objects </em><em>is </em><em>2</em><em>.</em><em>5</em><em> </em><em>cm</em><em>, if the attraction between them is 8 </em><em>units.</em>

<em><u>Learn more about universal law of gravitation here brainly.com/question/27244479</u></em>

<em>Thanks </em><em>for </em><em>joining </em><em>brainly </em><em>community</em><em>!</em>

7 0

2 years ago