Answer:
c it does not move as the tire stops and applys friction
Explanation:
Answer:
D) F
Explanation:
Let m and M be the mass of the balls A and B respectively and r be the distance between the two balls. The magnitude of attractive gravitational force experienced by the balls due to each other is given by the relation :
......(1)
Now, if the masses of both the balls gets doubled as well as there separation distance also gets doubled, then let F₁ be the new gravitational force acting on them.
Since, New mass of ball A = 2M
New mass of ball b = 2m
Distance between the two balls = 2r
Substitute these values in equation (1).
Using equation (1) in the above equation.
F₁ = F
ببيع ما عندي رصيد انا ما في رصيد شي عندي شغل رصيد انا ما في شي ما عندي عندي شي عندي شغل عنما في رصيد عندي
Answer:
Explanation:
mass of object, m = 3 kg
spring constant, K = 750 n/m
compression, x = 8 cm = 0.08 m
angle of gun, θ = 30°
(a) As the ball is launched, it has some velocity due to the compression in the spring, so it has some kinetic energy.
(b) Let v be th evelocity of ball at the tim eof launch.
by using the conservation of energy
1/2 Kx² = 1/2 mv²
750 x 0.08 x 0.08 = 3 x v²
v = 1.265 m/s
By use of the formula of maximum height
h = 0.02 m
h = 2 cm
<h3>
Answer:</h3>
2.5 mg
<h3>
Explanation:</h3>
<u>We are given</u>;
- Original mass of I-131 is 40.0 mg
- Half life of I-131 is 8 days
- Number of days 32 days
We are required to determine the mass that will remain;
N = N₀ × 0.5^n
where, N is the remaining mass, N₀ is the original mass, and n is the number of half lives.
Therefore;
n = time ÷ half life
= 32 days ÷ 8 days
= 4
Therefore;
Remaining mass = 40.0 mg × 0.5^4
= 2.5 mg
Hence, the remaining mass of I-131 after 32 days is 2.5 mg