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Anastaziya [24]
2 years ago
15

What are wind and water erosion not likely to affect

Physics
2 answers:
zavuch27 [327]2 years ago
5 0

Answer:

Tides, bodies of water

Explanation:

ira [324]2 years ago
3 0

Answer:

Wind and water erosion are least likely to affect igneous sills and cooled lava flows

Explanation:

Limestone             basalt and quartzite        are also unlikely to undergo erosion or weathering, as are sandstone and chert. Soil and soft rocks such as clays erode very quickly without protection.

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Why is it better to use the metric system, rather than the English system, in scientific measurement?
fiasKO [112]

A. The English system uses one unit for each category of measurement.

4 0
3 years ago
Read 2 more answers
In the 25 ft Space Simulator facility at NASA's Jet Propulsion Laboratory, a bank of overhead arc lamps can produce light of int
Aleonysh [2.5K]

Answer:

a) <em>8.33 x 10^-6 Pa</em>

b) <em>8.23 x 10^-11 atm</em>

c) <em>1.67 x 10^-5 Pa</em>

d) <em>1.65 x 10^-10 atm</em>

<em></em>

Explanation:

Intensity of the light I = 2500 W/m^2

speed of light c<u> </u>= 3 x 10^8 m/s

a) we know that the pressure for for a totally absorbing surface is given as

P_{abs} = I/c = 2500/(3 x 10^8) = <em>8.33 x 10^-6 Pa</em>

b) 1 atm = 101325 Pa

P_{abs} = (8.33 x 10^-6)/101325 = <em>8.23 x 10^-11 atm</em>

c) for a totally reflecting surface

P_{ref} = 2I/c = twice the value for totally absorbing

P_{ref}  = 2 x 8.33 x 10^-6 = <em>1.67 x 10^-5 Pa</em>

d)  1 atm = 101325 Pa

P_{ref} = 2 x 8.23 x 10^-11  = <em>1.65 x 10^-10 atm</em>

8 0
2 years ago
Without Newton’s third law of motion, what would an object sitting on a table do?
Angelina_Jolie [31]

Newton's third law: If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A. This law represents a certain symmetry in nature: forces always occur in pairs, and one body cannot exert a force on another without experiencing a force itself.

8 0
3 years ago
Read 2 more answers
The height of an object is 10 cm, and the height of its image is 6 cm. What is the magnification?
kipiarov [429]

magnification = \bf\dfrac{height of image}{height of object}

= \bf\dfrac{6cm}{10cm}

= 0.6

3 0
2 years ago
You can use any coordinate system you like in order to solve a projectile motion problem. To demonstrate the truth of this state
Aleks04 [339]

Explanation:

It is given that,

Height of the building, h = 44 m

Initial horizontal velocity, u_x=ucos\theta=8.6\ m/s

Initial vertical velocity, u_y=usin\theta=10.5\ m/s

It can be assumed to find the maximum height of the projectile and time taken to reach the maximum height.

The formula for the maximum height is given by :

H=\dfrac{(u\ sin\theta)^2}{2g}

g is the acceleration due to gravity

H=\dfrac{(10.5)^2}{2\times 9.8}=5.625\ m

The total maximum height, h' = h + H

h'=44+5.625=49.625\ m

The formula for the time of flight is given by :

t_{max}=\dfrac{u\ sin\theta}{g}

t_{max}=\dfrac{10.5}{9.8}=1.07\ s

Hence, this is the required solution.

3 0
3 years ago
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